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mars1129 [50]
1 year ago
9

Need help on solving percent mixture problems using a linear equation

Mathematics
1 answer:
leonid [27]1 year ago
5 0

Answer:

Amount inverted in Fund B: $6000

Explanation:

Here are the facts we know.

For Fund A:

$4000 invested,

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PLEASE HELP!! i dont understand it
andreev551 [17]

Answer:

 a.  y^ -1 = e^x    +2

Step-by-step explanation:

y = ln (x-2)

Exchange x and y

x = ln (y-2)

Solve for y

Raise each side with a base of e

e^ x = e^(ln(y-2)

e^x = y-2

Add 2 to each side

e^x  +2 =y

6 0
3 years ago
Simplify the algebraic expression (4b5 - 7) + (12b5 - 1)
ioda

Answer:16b square root of 5 -8

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Tom planted 1/2 of an 8-ft by 9-ft garden with vegetables. He planted tomatoes in 1/3 of the vegetable garden and corn in the re
ser-zykov [4K]

Answer:

Corn was planted in 24 sq.ft. of the vegetable garden.

Step-by-step explanation:

Length of garden = 9 ft

width of garden = 8 ft

Hence we will first find the total area of garden.

Total area of garden = length × width = 8 \times 9 = 72ft^2

He planted 1/2 of the garden with vegetables.

Hence.

Area of Vegetables garden = \frac{1}{2}\times \textrm{Total Area of Garden} = \frac{1}{2}\times 72 = 36ft^2

He planted tomatoes in 1/3 of the vegetable garden and corn in the rest

Area in which tomatoes was planted = \frac{1}{3}\times \textrm{Area of Vegetables Garden} = \frac{1}{3}\times 36 = 12ft^2

Hence Area in which corn were planted = Area of Vegetables garden - Area in which tomatoes was planted = 36ft^2-12ft^2=24ft^2

Hence Area of vegetable garden in which corn was planted is 24 sq.ft.

7 0
3 years ago
Which one of these is the correct answer?
sukhopar [10]

Answer:

the top answer.............

8 0
2 years ago
Help please ..........
Pie

Answer:

#2 is the closest to the actual roots.

Step-by-step explanation:

12x^{3} -65x^{2} +24x+10=0

\frac{2}{3} is not a root, but 0.68078 is.

The other roots are -0.24572 and 4.9816.  The closest option is #2.

5 0
2 years ago
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