PLEASE HELP!! i dont understand it

Mathematics

1 answer:

andreev551 [17]3 years ago

6 0

Answer:

a. y^ -1 = e^x +2

Step-by-step explanation:

y = ln (x-2)

Exchange x and y

x = ln (y-2)

Solve for y

Raise each side with a base of e

e^ x = e^(ln(y-2)

e^x = y-2

Add 2 to each side

e^x +2 =y

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The correct equilibrium constant expression for this equation is;

$\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}$

Given

Consider the equation below.

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<h3>What are Species?</h3>

In an equilibrium constant expression, you do not include the solid substances; only gases and dissolved substances.

<h3>Equilibrium constant expression;</h3>

It is the quotient of the product of the concentrations of the species on the right-hand side of the equilibrium equation, each raised to its corresponding coefficient, and the product of the concentrations of the species on the left-hand side, each raised to its corresponding coefficient.

Therefore,

The correct equilibrium constant expression for this equation is;

$\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}$

Hence, the correct equilibrium constant expression for this equation is;

$\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}$ .

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