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SOVA2 [1]
3 years ago
13

Tom planted 1/2 of an 8-ft by 9-ft garden with vegetables. He planted tomatoes in 1/3 of the vegetable garden and corn in the re

st . What is the area planted in corn
Mathematics
1 answer:
ser-zykov [4K]3 years ago
7 0

Answer:

Corn was planted in 24 sq.ft. of the vegetable garden.

Step-by-step explanation:

Length of garden = 9 ft

width of garden = 8 ft

Hence we will first find the total area of garden.

Total area of garden = length × width = 8 \times 9 = 72ft^2

He planted 1/2 of the garden with vegetables.

Hence.

Area of Vegetables garden = \frac{1}{2}\times \textrm{Total Area of Garden} = \frac{1}{2}\times 72 = 36ft^2

He planted tomatoes in 1/3 of the vegetable garden and corn in the rest

Area in which tomatoes was planted = \frac{1}{3}\times \textrm{Area of Vegetables Garden} = \frac{1}{3}\times 36 = 12ft^2

Hence Area in which corn were planted = Area of Vegetables garden - Area in which tomatoes was planted = 36ft^2-12ft^2=24ft^2

Hence Area of vegetable garden in which corn was planted is 24 sq.ft.

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Answer:

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Step-by-step explanation:

<u>Substitution</u>

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The solution is (x, y) = (0, -2248).

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<u>Elimination</u>

Subtract the first equation from the second.

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<em>Additional comment</em>

If you think for a bit about what the graph looks like, you realize both lines cross at their y-intercept, (0, -2248). That point of intersection is the solution to the system of equations.

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