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Free_Kalibri [48]
1 year ago
13

What is the sum of the following vectors? Write your answer, what magnitude and direction the vector will have?

Physics
1 answer:
Brrunno [24]1 year ago
5 0

The magnitude and direction of the object's displacement is 7 m and west direction respectively.

<h3>What is displacement?</h3>

The displacement of an object is the change in the position of the object. Displacement is a vector quantity because it has both magnitude and direction.

To find the sum of the vectors, we find the displacement of the vectors.

Initial position of the vector = 10 m east

final position of the vector = 3 m west

displacement of the vector = final position - initial position

displacement of the vector = 3 m - 10 m

displacement of the vector = - 7 m

magnitude of the displacement = 7 m

direction of the displacement = west

Thus, the magnitude and direction of the object's displacement is 7 m and west direction respectively.

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

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when an object is immersed in liquid at rest,why is the net force on the object is the horizontal direction equal to zero?​
Marizza181 [45]

Answer:

The pressure is the same on points that are at the same level but on opposite sides.

6 0
3 years ago
Find the work done by the force ​F = xyi +(y-x)j over the straight line from​ (-1,1)to (3,-3). The amount of work done is ___?
dalvyx [7]

Answer:

amount of work done isW  =  \frac{-4}{3}      

Explanation:

Formula for work done by force field

W = \int F. dr = \int_{t_o}^{t_1} f(r(t)) r'(t) dt

where

r(t) is parametrization of line

as it is straight line so

r(t) = 1- t) r_o + tr_1   0 \leq t \leq 1

thus,

r(t) = (1-t)(-1,1) + t(3,-3)

    = (-1+t,1-t) + (3t - 3t)

   = (-1+t +3t, 1-t-3t)

r(t) = (4t -1, 1- 4t)

r'(t) = (4,-4)

putting value in above integral

\int_{0}^{1} ((4t -1,1-4t)). (4,4) dt = \int_{0}^{1} (-(4t -1)^2 , 2-8t).(4,-4) dt

                                                  = \int_{0}^{1} (-16 t^2 + 8t -1,2-8t) .(4,-4) dt

                                                  =\int_{0}^{1} (4(-16t^2 +8t -1) -4(2-8t)) dt

                                                   = 4[ -16 \frac{t^3}{3} + 16\frac{t^2}{2} - 3t]_{0}^{1}

\int_{0}^{1} ((4t -1,1-4t)). (4,4) dt = \frac{-4}{3}                                                        

3 0
4 years ago
In a nuclear experiment a proton with kinetic energy 3.0 MeV moves in a circular path in a uniformmagnetic field. What energy mu
dlinn [17]

Answer:

a)     K = 3 MeV   b)   K=  1.5 MeV

Explanation:

We can solve this experiment using the equation of the magnetic force with Newton's second law, where the acceleration is centripetal.

        F = q v x B

We can also write this equation based on the modules of the vectors

        F = qv B sin θ

With Newton's second law

       F = ma

       F = m v² / r

       q v B = m v² / r

       v = q B r / m

The kinetic energy is

       K = ½ m v²

Substituting

       K = ½ m (q B r/ m)²

       K = ½ B² r²  q² / m

       K = (½ B² R²)  q²/m

The amount in brackets does not change during the experiment

      K = A  q² / m

For the proton

     K = 3.0 10⁶eV (1.6 10⁻¹⁹ J / 1eV) = 4.8 10⁻¹³ J

With this data we can find the amount we call A

    A = K  m/q²

    A = 4.8 10⁻¹³ 1.67 10⁻²⁷ /(1.6 10⁻¹⁹)²

    A = 3.13 10⁻²

With this value we can write the equation

    K = 3.13 10⁻²  q² / m

Alpha particle

    m = 4 uma = 4 1.66 10⁻²⁷ kg

   K = 3.13 10⁻² (2 1.6 10⁻¹⁹)² / 4.0 1.66 10⁻²⁷

   K = 4.82 10⁻¹³ J ((1 eV / 1.6 10⁻¹⁹ J) = 3 10⁶ eV

   K = 3 MeV

Deuteron

   K = 3.13 10⁻² (1.6 10⁻¹⁹)²/2 1.66 10⁻²⁷

   K = 2.4 10⁻¹³ J (1eV / 1.6 10⁻¹⁹J)

   K = 1.5 10⁶ eV

   K=  1.5 MeV

6 0
3 years ago
A 3.62 g bullet moving at 270 m/s enters and stops in an initially stationary 2.30 kg wooden block on a horizontal frictionless
scZoUnD [109]
Momentum before collision must be equal to momentum after collision

(m1<span> + m</span>2)v = m1v1<span> + m</span>2v<span>2</span>



3.62g*270 m/s=2.30kg* (x)
convert the units to be the same that is convert the kg mass to grams
1kg=1000g
2.30kg=y
230/100*1000=2300g
3.62*270=2300X
977.4g/m/s=2300X
977.4/2300=0.4250M/S
Finding a velocity after the gun is embedded on the block of wood
3.62*270+2300g*0.425=(3.62+2300)*V
977.5+977.5=2303V
1955=2303V
V=1955/2303
V=0.8489M/S

5 0
3 years ago
A calculator has a resistance of 22 Ω. What is the power rating for this calculator when connected to a 1.5 V battery?
GREYUIT [131]

Answer:

33

Explanation:

3 0
3 years ago
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