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Mademuasel [1]
3 years ago
14

When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. Suppose anot

her bomb is tested, and 3.6 grams of matter are converted into energy. How many joules of energy are released by the explosion?
Physics
1 answer:
Softa [21]3 years ago
3 0

Answer:

1.08 * 10^{14} J

Explanation:

Energy and mass are related by the famous equation developed by Albert Einstein:

E = mc^2

where m = mass and c = speed of light

This equation explains that an object with very small mass can produce a large amount of energy in reactions such as a nuclear reaction.

Hence, the energy produced by the explosion of a Plutonium bomb containing 3.6 grams of matter is:

E = 3.6 * 10^{-3} * (3 * 10^8)^2

E = 1.08 * 10^{14} J

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Guys I need help with my homework please !!!!
Sergio [31]

Answer:

(a) To draw water from a well we have to pull at the rope.

(b) A charged body attracts an uncharged body towards it.

(c) To move a loaded trolley we have to pull it.

(d) The north pole of a magnet repels the north pole of another magnet.

Explanation:

Just trust me

6 0
3 years ago
Explain how energy allows a paper clip to be attracted to a magnet
ELEN [110]

I really don’t know maybe energy from the poles just attaches and the soil comes and energy lifts the matter of soil and the magnet follows and lifts and goes up to the soil and the poles attach the magnet to the soil and the energy lifts the magnet and the soil follows and it is attracted to the magnet

6 0
3 years ago
Read 2 more answers
f the CD rotates clockwise at 500 rpmrpm (revolutions per minute) while the last song is playing, and then spins down to zero an
vazorg [7]

Answer:

The magnitude of the angular acceleration is  a =  20.14 rad/s^2

Explanation:

From the question we are told that

   The angular speed of CD is  w_{CD} =  500 rpm =  \frac{500  rpm}{\frac{60 \ s }{1 \ min} } * \frac{2 \pi }{ 1 \ rev} = 52.37 rad/s

    time taken to decelerate is t_{CD} =  2.60\ s

    The final angular speed is  w_f= 0 \ rad/s

The angular acceleration is mathematically represented as

         a =  \frac{w_f - w_{CD}}{t}

substituting values

          a =  \frac{0 - 52.37}{2.60}

         a =  - 20.14 rad/s^2

The negative sign show that the CD is decelerating  but the magnitude is

       a =  20.14 rad/s^2

   

3 0
3 years ago
Need help with this physics question!
Fynjy0 [20]

Answer:

omg i need help with the same answer lol

Explanation:

i wish i can help but i need help on this hehe

6 0
3 years ago
A ball is dropped and falls with an acceleration of 9.8 m/s2 downward. It hits the ground with a velocity of 49 m/s downward. Ho
il63 [147K]
Hey!

NOTE-:

u= initial velocity
v= final velocity
g= acceleration due to gravity
t= time

u= 0
v= 49 m/s
t=?
g= 9.8 m/s^2

Using first equation of motion -

v-u=at
49-0= 9.8×t
49 = 9.8t
49/9.8= t
t= 5 second


Hope it helps...!!!
6 0
3 years ago
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