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3 years ago

Light incident on a surface at an angle of 45° undergoes diffused reflection. At what angle will it reflect?

2 answers:

8 0

<span>The correct answer is option D. i.e. at any angle between -90 and 90 degrees. In the diffused reflection ,the surface is rough and the direction of light in not the same as the incident light. It can be reflected at any angle. </span>

Korvikt [17]3 years ago

3 0

Answer:

D. at any angle between -90° and 90°

Explanation:

First of all, we need to understand the difference between specular reflection and diffuse reflection:

- Specular reflection occurs when the surface hit by the light is perfectly smooth. In this case, the law of reflection states that the angle at which the light is reflected is equal to the angle of incidence of the light (measured relative to the normal to the surface)

- Diffuse reflection occurs when the surface hit by the light is rough. In this case, the law of reflection is still valid for every ray of light hitting the surface; however, due to the imperfections of the surface, each ray of light hits the surface at a different angle of incidence. This means that the angle of reflection for each ray will be different, so light is reflected in any direction between -90 degrees and 90 degrees, which corresponds to the minimum and the maximum angle of reflection measured relative the normal to the surface.

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A man can jump 1.5 m on earth. calculate the approximate

Olegator [25]

Answer:

18 m

Explanation:

G = Gravitational constant

m = Mass of planet = $\rho V$

$\rho$ = Density of planet

V = Volume of planet assuming it is a sphere = $\dfrac{4}{3}\pi r^3$

r = Radius of planet

Acceleration due to gravity on a planet is given by

$g=\dfrac{Gm}{r^2}\\\Rightarrow g=\dfrac{G\rho V}{r^2}\\\Rightarrow g=\dfrac{G\rho \dfrac{4}{3}\pi r^3}{r^2}\\\Rightarrow g=\dfrac{4G\rho\pi r}{3}$

So,

$g\propto \rho r$

Density of other planet = $\rho_p=\dfrac{1}{4}\rho_e$

Radius of other planet = $r_p=\dfrac{1}{3}r_e$

$\dfrac{g_e}{g_p}=\dfrac{\rho_e r_e}{\rho_p r_p}\\\Rightarrow \dfrac{g_e}{g_p}=\dfrac{\rho_e r_e}{\dfrac{1}{4}\rho_e\times \dfrac{1}{3}r_e}\\\Rightarrow \dfrac{g_e}{g_p}=12\\\Rightarrow g_p=\dfrac{g_e}{12}\\\Rightarrow g_p=\dfrac{9.8}{12}$

Since the person is jumping up the acceleration due to gravity will be negative.

From kinematic equations we have

$v^2-u^2=2g_es\\\Rightarrow u^2=v^2-2g_es\\\Rightarrow u^2=0-2\times -9.8\times 1.5\\\Rightarrow u^2=2\times 9.8\times 1.5$

On the other planet

$v^2-u^2=2g_ps\\\Rightarrow s=\dfrac{v^2-u^2}{2g_p}\\\Rightarrow s=\dfrac{0-(2\times 9.8\times 1.5)}{2\times -\dfrac{9.8}{12}}\\\Rightarrow s=18\ \text{m}$

The man can jump a height of 18 m on the other planet.

5 0

2 years ago

Can you help me answer this?

Pavel [41]

The answer is D. If you aren't consistent with your drop positions, then your data may be invalid. To be frank: it basically screws over the experiment.

5 0

3 years ago

You are riding a bicycle home from school. You average 5 meters per second and you are headed south.

olchik [2.2K]

Answer:

(OD) Velocity

Explanation:

Here, the rider is moving with a steady speed (5 m/s) towards south. In this example, we have magnitude as well as direction. Since velocity is a vector quantity, thus we can determine the velocity of the rider.

5 0

2 years ago

Determine the ratio of the resistivity of pure water to silver?

shutvik [7]

Silver is a very good conductor, this means its resistivity is very low (from table, we can check the precise value, which is $\rho_s = 1.6 \cdot 10^{-8} \Omega m$ ).

Pure water, instead, is a very bad conductor, this means its resistivity is very high, of order of $k \Omega \cdot m$ ( $10^3 \Omega m$ ). Even without knowing the precise value of the pure water resistivity, we can estimate the ratio between the pure water resistivity and the silver resistivity by comparing the two orders of magnitude:
$r= \frac{10^3 \Omega m}{10^{-8} \Omega m} \sim 10^{11}$

Therefore, we can say that the correct answer is
$3 \cdot 10^{11} : 1$

3 0

2 years ago

8. A crate of bananas weighing 3000 N is shipped from South America to New York, where it

LiRa [457]

Answer:

Mechanical advantage = 15

Explanation:

Given the following data;

Output force = 3000N

Input force = 200N

To find the mechanical advantage;

Mechanical advantage = output force/input force

Substituting into the equation, we have

Mechanical advantage = 3000/200

Mechanical advantage = 15

3 0

2 years ago