17.54% is the probability that 5 messages are received in 1 hour.
The chance that X reflects the number of successes of a random variable in a Poisson distribution is provided by the following formula:
P(X = x) = ( × ) ÷ x!
In where x is the number of successes, e is the Euler number, and u is the mean in the specified time frame.
In this case, the average message rate is 5 messages per hour.
The probability of receiving 5 texts in one hour.
Determine the value of P for x = 5 and u = 6.
P(X = x) = ( × ) ÷ 5!
P(X = x) = 21.0560 ÷ 5!
P(X = x) = 0.1754
There is a 17.54% chance that 5 messages will be received in 1 hour.
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