The weight of a 170 cm steel bar will be 5 Kg
Step-by-step explanation:
Derek uses a 136 cm flat steel bar that weighs 4 kg to make rack in the garage.
1 kg = 1000 gm
So the weight of 1 cm steel bar will be
kg
Weight of 1 cm bar =
gm
Let the weight of a 170 cm steel bar will be
×
gm
⇒
×
gm
⇒ 5000 gm
⇒5 kg
Hence, the weight of a 170 cm steel bar will be 5 Kg
Answer:
The correct option is C). (9,4)
The coordinates of a point N is (9,4)
Step-by-step explanation:
Theory: If point P(x,y) lies on line segment AB and AP: PB=m:n, then we say P divides line AB internally in ratio of m:n and Point is given by
P=
Given that point, M is lying somewhere between point L and point N.
The coordinates of a point L is (-6,14)
The coordinates of a point M is (-3,12)
Also, LM: MN = 1:4
We can write as,
Let,
Point L(-6,14)=(X1, Y1)
Point M(-3,12)=(x,y)
Point N is (X2, Y2)
m=1 and n=4
M(-3,12)=
M(-3,12)=
M(-3,12)=

(-15)=X2-24
X2=9

(60)=Y2+56
Y2=4
Thus,
The coordinates of a point N is (9,4)
Result: The correct option is C). (9,4)
9514 1404 393
Answer:
- 16,965 mm/min
- 90π ≈ 282.7 radians/min
Step-by-step explanation:
The circumference of the CD is ...
C = πd
C = π(120 mm) ≈ 376.99 mm
This is the distance a point on the edge of the CD will travel when making one revolution. It will travel 45 times this far when making 45 revolutions:
(376.99 mm/rev)(45 rev/min) ≈ 16,965 mm/min
__
There are 2π radians in each revolution, so the angular speed is ...
(2π rad/rev)(45 rev/min) = 90π rad/min ≈ 282.7 rad/min
Answer:
(0,3) is the solution set for given system.
Step-by-step explanation:
Given that:
3x+4y=12 ------- eq1
2x-3y= -9 ------- eq2
Multiplying eq1 with 2 and eq2 with 3 we get:
6x + 8y = 24 --------- eq1
6x - 9y = -27 -------- eq2
Subtracting eq2 from 1 we get:
17y = 51
Dividing both sides by 17 we get:
y = 3
Putting value of 3 in eq1 we get:
3x + 4(3) = 12
3x + 12 = 12
3x = 0
Dividing both sides by 3
x = 0
So the solution set will be: (0,3)
i hope it will help you.