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2 years ago

6) Name the following compounds a. S2Cl3 B.KNO3 C.NH4Br

1 answer:

5 0

The name of the three compounds are Disulfur Dichloride, Potassium nitrate and Ammonium bromide respectively.

<h3>What are the names of the given compounds?</h3>

1. The name of the first compound is Disulfur Dichloride.

Disulfur Dichloride is a type of inorganic compound comprise of sulfur and chlorine. There are also many other names which we can be used like sulfur monochloride, disulphur dichloride and sulphur monochloride. It is used to show C-S bonds.

2. The name of the second compound is Potassium nitrate.

Potassium nitrate is a compound that belong to the alkali metal nitrate. Potassium nitrate is also known as Indian saltpetre. The potassium nitrate is present in the nature but in the form of mineral. The potassium nitrate is used for making the explosives, matches, rocket fuel and fireworks.

3.The name of the third compound is Ammonium bromide.

Ammonium bromide is a type of compound that contains ammonium salt of hydrobromic acid. It can melt easy on providing heat. It is also soluble in water. It gives yellow colour. Ammonium bromide is the weak acid.

So we can conclude that the name of the three compounds are Disulfur Dichloride, Potassium nitrate and Ammonium bromide respectively.

Learn more about Potassium Nitrate here: brainly.com/question/16419109

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Covalent bonding occurs between two oxygen atoms to form O2. What's the partial charge on each oxygen atom in 02?

Alik [6]

Answer:

Both oxygen atoms have zero partial charge.

Explanation:

In covalent bonds, electrons are shared between the two bonding atoms. The shared electron pair of the covalent bond is positioned between the nuclei of the two bonding atoms.

A covalent bond may be formed between two or more elements of different electronegativities. When a difference in electro negativity exists between these atoms in a covalent bond, the molecule becomes polarized. The shared electron pair of the covalent bond becomes closer to the nucleus of the more electronegative atom (s). This more electronegative atom (s) becomes partially negative while the other atom becomes partially positive.

When the two bonding atoms are of equal electronegativities such that the electro negativity difference between the bonding atoms is zero, there is now no difference in electro negativity and no consequent partial charges.

Since the two oxygen atoms have the same electro negativity, there is no difference in electronegativity, hence there is no partial charge between the two oxygen atoms.

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3 years ago

Disponemos de 3 moles de de sulfuro de hidrógeno (H S) 2

jonny [76]

Answer:

don't understand your language

6 0

3 years ago

Consider the reaction below. 2K+Br2------>2K+ +2Br-

sergeinik [125]

Answer: only Br2.

Justification.

In a chemical reaction the element that gains electrons experiments a reduction in its oxidation state, that is why it is said that it is reduced.

So, to know what element is being reduced you need to calculate the oxidation states of the elements involved.

Here I indicate the oxidation states of each element if the reaction putting them inside parenthesis:

Reactants side          Products side

K (0) K (1+)

Br (0)                          Br(1-)

So, K lost one electron, increasing its oxidation statefrom 0 to 1+, meaning that it is being oxidized.

And, each atom of Br gained one electron, reducing its oxidation state from 0 to 1-, meaning it is being reduced.

Therefore, the answer is that Br2 is the substance being reduced.

3 0

4 years ago

Read 2 more answers

If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.45 J/g･°C) that can be heated from 22.5°C to

inysia [295]

Answer:

The correct answer will be "18.25 g".

Explanation:

The given values are:

Specific heat,

C = 0.45 J/g･°C

Heat involved,

q = 801 J

Temperature,

ΔT = 120.0°C-22.5°C

= 97.5°C

As we know,

⇒ $C = \frac{q}{m \Delta T}$

On substituting the given values, we get

⇒ $0.45=\frac{801}{m(97.5)}$

⇒ $m = 18.25 \ g$

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4 years ago

Construct a simulated proton-decoupled 13C NMR spectrum for tert-butyl alcohol. Drag the resonance signal icon to the appropriat

atroni [7]

Answer:

The ¹³C-NMR Spectrum of tert-butyl alcohol will show only two signals.

(i) Signal at around 31 ppm:

This signal towards upfield is for the carbon atoms which are more shielded and are having rich electron surroundings. The height of peak at y-axis shows the number of carbon atoms as compared to other peaks. In this case it is three times the height of second signal hence, it shows that this peak corresponds to three carbon atoms.

(ii) Signal at around 70 ppm:

This signal towards downfield is for the carbon atom which is more deshielded and is having electron deficient surrounding. As compared to the second signal the height of this peaks corresponds to only one carbon. And the deshielded environment shows that this carbon is directly attached to an electronegative element.

4 0

4 years ago