Question

If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.45 J/g･°C) that can be heated from 22.5°C to 120.0°C?

Answer 1

Answer:

The correct answer will be "18.25 g".

Explanation:

The given values are:

Specific heat,

C = 0.45 J/g･°C

Heat involved,

q =  801 J

Temperature,

ΔT = 120.0°C-22.5°C

     = 97.5°C

As we know,

⇒  $C = \frac{q}{m \Delta T}$

On substituting the given values, we get

⇒  $0.45=\frac{801}{m(97.5)}$

⇒  $m = 18.25 \ g$