Part 1 (non-ideal behavior ):
we will use Van der Waals formula:
P = (nRT/(V-nb)) - (n^2 a/V2)
when n (moles of H2) = 18 g / 2 = 9 moles
R (constant) = 0.0821
T(tempreature in kelvin = 20 +273 = 293 K
V(Volume) = 1 L
a (constant for H2) = 0.2476
b(constant for H2) = 0.02661
So by substitution:
∴P = (9*0.0821*293/(1-(9*0.02661))) - (9^2*0.2476/1)
∴P ≈264.6 atm
Part 2 (ideal behavior):
we will use the ideal gas formula :
PV = nRT
when we have n = 9
R= 0.0821
T=293 K
V= 1 L
∴P = (9*0.0821*293)/1 L
∴P = 216.5 atm
Thomson’s plum pudding model of the atom was later found to be inadequate following the discovery of the nucleus by Rutherford.
You would have to give 0.25 mL of the drug every 15 s.
This is a problem in unit conversion.
You have to convert seconds → minutes → milligrams of drug → millilitres of drug
15 s ×
1 min
60 s
×
37.5 mg
15 min
×
1 mL
2.5 mg
= 0.25 mL
You would have to give 0.25 mL of the drug every 15 s.
Answer:
84.259 kPa
Explanation:
We know that:
1 kPa is approximately equal to 7.5 mmHg
Therefore, to convert 632 mmHg to kPa, we will simply use cross multiplication as follows:
1 kPa .................> 7.5006 mmHg
?? kPa ................> 632 mmHg
632 mmHg = (632*1) / (7.5006) = 84.259 kPa
Hope this helps :)
B less because higher in elevation