The correct mole ratio of K₃PO₃ and KNO₂ in the chemical reaction is 1 : 3
<h3>Balanced equation</h3>
3Mg(NO₂)₂ (aq) + 2K₃PO₃ (aq) -> Mg₃(PO₃)₂(aq) + 6KNO₂(aq)
from the balance equation,
- The number of mole of K₃PO₃ = 2 moles
- The number of mole of KNO₂ = 6 moles
<h3>How to determine the mole ratio of K₃PO₃ and KNO₂</h3>
- Number of mole of K₃PO₃ = 2 moles
- Number of mole of KNO₂ = 6 moles
- Mole ratio of K₃PO₃ and KNO₂ =?
Mole ratio = mole of K₃PO₃ / mole of KNO₂
Mole ratio of K₃PO₃ and KNO₂ = 2 / 6
Mole ratio of K₃PO₃ and KNO₂ = 1 : 3
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Answer:
ΔG° = - RTLnK is used to find the standard cell potential given the equilibrium constant
Explanation:
for an ideal disolution:
⇒ ΔG = RT∑ni LnXi
∴ ΔG = ( μi - μi*)ni
∴ μ : chemical potential
∴ μ*: chem. potential of the pure component at T and P.
⇒ ΔG = μi - μi* = RT LnXi
for a equilibrium reaction:
⇒ ∑ νi*μi = 0
⇒ ΔGr = ΔG°+ RT Ln Kx = 0
⇒ ΔG° = - RT LnKx
Answer:
To calculate the volume we must first find the number of moles
Number of moles (n ) = mass / Molar mass (M)
Since oxygen is diatomic
M of oxygen = 16 × 2 = 32g/mol
n = 16 / 32 = 0.5mol
Next we use the formula
V = n × V(dm³)
where V is the volume
V(dm³) is the volume of 1 mole of a substance at s.t.p which is
22.4dm³
Volume of oxygen gas at s.t.p is
0.5 × 22.4dm³
= 11.20dm³
Hope this helps you
Answer:
Explanation:
Most of this ancient space rubble can be found orbiting the Sun between Mars and Jupiter within the main asteroid belt. Asteroids range in size from Vesta – the largest at about 329 miles (530 kilometers) in diameter – to bodies that are less than 33 feet (10 meters) across.
