Increasing I think dryyhiiouiiiiuyutff
If <em>y</em> = cos(√<em>x</em>), then by the chain rule
d<em>y</em>/d<em>x</em> = d/d<em>x</em> [cos(√<em>x</em>)]
d<em>y</em>/d<em>x</em> = - sin(√<em>x</em>) d/d<em>x</em> [√<em>x</em>]
d<em>y</em>/d<em>x</em> = - sin(√<em>x</em>) (1 / (2√<em>x</em>))
d<em>y</em>/d<em>x</em> = - 1/2 sin(√<em>x</em>) / √<em>x</em>
The choices can be found elsewhere and as follows:
<span>a. points on a line
b. random points
</span>c. points on a horizontal line <span>
d. points on a curvy line
I believe the correct answer is option D. The </span><span>data represented on a scatterplot that depicts an exponential model would be points on a curvy line. Hope this answers the question. Have a nice day.</span>
Note that what we want is to compress any point (a, b) in the parent function, to (a, b/4).
(a, b) is a point of the graph of the function

, thus we can rewrite the point as:

.
This point is compressed to

.
This means that the function we are looking for is

.
Answer: <span>t(x)=1/4x^7
</span>
Answer:
add the equation to eliminate the variable