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Zigmanuir [339]
2 years ago
14

A headline in a major newspaper read, "Breast-fed youth found to do better in school."a. Do you thinkthis statement was based on

an observational study or a randomized experiment? Explain.b. Given your answer in part (a), which of these two alternative headlines do you think would be preferable: "Breast-feeding leads to better school performance" or "Link found between breast-feeding and school performance"? Explain.
Mathematics
1 answer:
Maurinko [17]2 years ago
3 0

Answer:

Randomized experiment

Step-by-step explanation:

Such a statement is said to be Randomized experiment as the kids in the school have been selected at random and their performances are observed and recorded. Later it is inquired if they are breast fed or not. This information is later assessed and a conclusion is reached. This type of research or experiment is Randomized experiment.

Considering that the experiment is Randomized, the statement should be "Link found between breast-feeding and school performances". This statement does not restrict the performances of the student specifically on breast-feeding but shows a probable affect of it.

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If (x-7) is a factor of 2x^2-11x+k, what is the value of k
kondaur [170]

If x-7 =0

Then x =7

Substitute x=7 into f(x):

2(7)^2 - 11(7) + k

= (98-77)+k

= 21+k

Therefore k=-21 because 21+(-21)=0

4 0
3 years ago
Find the values of the variables in the parallelogram. The diagram is not drawn to scale. Use fear rams involving parallel lines
Anarel [89]
X = 21; y = 56; z = 103
3 0
3 years ago
Find mean, median and mode of 140, 130, 90, 80, 60, 50, 30, 20, 10, 0
Alecsey [184]
For the mean you would have to add up all the numbers up and divide by the amount of numbers. For your problem you would get 610/10= 61. 

For the median you would arrange all the numbers in order from least to greatest and cancel one from the left and one from the right each time. Since there is no middle number, the closest would be 50 and 60. Thus you you add 50+60 and get 110 and then divide by 2 giving you 55.

For the mode, there is no mode because none of the numbers repeat more than once.

I hope this clarifies your doubt. :)
3 0
3 years ago
which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1​
lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. y=\sec x

B. y= \tan x

C. y= \cot x

D. y= \csc x

Answer:

A. y=\sec x

D. y=\csc x

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: y=\sec x

We know that, the \sec x=\frac{1}{\cos x}

The range of \cos x is from -1 to 1 given as [-1, 1]. So,

|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1

Therefore, on removing the absolute sign, we rewrite the secant function as:

\sec x\leq -1\ or\ \sec x\geq 1\\

Therefore, the range of y=\sec x is all real numbers greater than or equal to 1 or less than or equal to-1​.

Choice B: y= \tan x

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: y= \cot x

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: y=\csc x

We know that, the \csc x=\frac{1}{\sin x}

The range of \sin x is from -1 to 1 given as [-1, 1]. So,

|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

\csc x\leq -1\ or\ \csc x\geq 1\\

Therefore, the range of y=\csc x is all real numbers greater than or equal to 1 or less than or equal to-1​.

6 0
3 years ago
A rectangle has an area of 144x^2-81. What is the length and the width?
Studentka2010 [4]

Answer:

thanks

Step-by-step explanation:

for asking this i need the answer too

6 0
2 years ago
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