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Oxana [17]
1 year ago
14

A circle has a radius of 98 units and is centered at (5.9,6.7) write the equation of the circle

Mathematics
1 answer:
Hoochie [10]1 year ago
6 0

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

radius = √98

center = (5.9,6.7)

equation of the circle​ = ?

Step 02:

Equation of the circle​

(x - a) ² + (y - b) ² = r ²

(a , b) = center

(x - 5.9) ² + (y - 6.7) ² = (√98) ²

(x - 5.9) ² + (y - 6.7) ² = 98

The answer is:

(x - 5.9) ² + (y - 6.7) ² = 98

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What is the standard form of the linear function that passes
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(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{4}}}\implies \cfrac{-3}{-2}\implies \cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{4})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2(y-1)=2\left( \cfrac{3}{2}(x-4) \right)}\implies 2y-2 = 3(x-4)\implies 2y-2=3x-12 \\\\\\ -3x+2y-2=-12\implies -3x+2y=-10\implies \stackrel{\times -1\textit{ to both sides}}{3x-2y=10}

7 0
2 years ago
If the sin 30 = 1/2, then which statement is true?
egoroff_w [7]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Write the equation of a line perpendicular to y=0.25x-7 and passes through the point -6,8
horrorfan [7]

the equation of a line perpendicular to y=0.25x-7 and passes through the point (-6,8) is y=-4x+30

Step-by-step explanation:

We need to write equation of line perpendicular to y=0.25x-7 and passes through the point (-6,8)

Since the line y=0.25x-7 is in slope-inetercept form y=mx+b

the slope of line m = 0.25

As, the new line is perpendicular to the given line so, slopes of lines that are perpendicular are: slope = -1/slope1

So, slope will be -1/0.25 = -4

Now, finding y-intercept.

y=mx+b8=4(-6)+b\\8=-24+b\\b=8+24\\b=30

So, value of y-intercept b = 30

Now the equation of the required line having slope m= -4 and b =30 will be:

y=mx+b\\y=-4x+30

So, the equation of a line perpendicular to y=0.25x-7 and passes through the point (-6,8) is y=-4x+30

Keywords: Equation of line, slope-intercept form

Learn more about slope-intercept form at:

  • brainly.com/question/12954015
  • brainly.com/question/1979240
  • brainly.com/question/2601054

#learnwithBrainly

3 0
3 years ago
Which graph represents the function y = 2/3x-2
Alina [70]

Answer:

C

Step-by-step explanation:

so the y-int is where the point is on the y-axis (0,X). Or, in this situation-2.

for slope, you just need to do rise over run, or up and down first then, left and right. If I do that for C, I go 2 up and 3 right. So the slope os 2/3 (P.S. up and right is positive, and down and left is negative)

7 0
3 years ago
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