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maria [59]
3 years ago
12

!!!!!!!!15 POINTS FOR ANSWERING THIS CORRECTLY!!!!!!!!

Mathematics
1 answer:
Georgia [21]3 years ago
4 0
<span> graph of y = [x] for -2 ≤ x ≤ 2 </span>

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On a coordinate plane, triangles R S T and L M N are shown. Triangle R S T has points (5, 5), (2, 1), and (1, 3). Triangle L M N
ivolga24 [154]

Answer:

LMN has a larger area

Step-by-step explanation:

Given

RST

R =(5,5)

S= (2,1)

T = (1,3)

LMN

L = (0,-1)

M= (2,-4)

N= (-2,-3)

Required

Compare both areas

The area of triangle is:

Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3|

For RST, we have:

Area = \frac{1}{2}|5*1 - 2*5 + 2*3 - 1*1 + 1*5 - 5*3|

Area = \frac{1}{2}|-10|

Remove absolute signs

Area = \frac{1}{2}*10

Area = 10

For LMN, we have:

Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3|

Area = \frac{1}{2}|0*-4-2*-1+2*-3--2*-4--2*-1-0*-3|

Area = \frac{1}{2}|-14|

Remove absolute signs

Area = \frac{1}{2}*14

Area = 7

<em>By comparing both areas, we can conclude that LMN has a larger area</em>

3 0
3 years ago
A hockey team is convinced that the coin used to determine the order of play is weighted. The team captain steals this special c
fredd [130]

Answer:

Since x= 12 (0.006461) does not fall in the critical region so we accept our null hypothesis and conclude that the coin is fair.

Step-by-step explanation:

Let p be the probability of heads in a single toss of the coin. Then our null hypothesis that the coin is fair will be formulated as

H0 :p 0.5   against   Ha: p ≠ 0.5

The significance level is approximately 0.05

The test statistic to be used is number of heads x.

Critical Region: First we compute the probabilities associated with X the number of heads using the binomial distribution

Heads (x)        Probability (X=x)                        Cumulative     Decumulative

0                        1/16384 (1)             0.000061     0.000061

1                         1/16384  (14)         0.00085             0.000911

2                       1/16384 (91)           0.00555             0.006461

3                       1/16384(364)         0.02222

4                       1/16384(1001)         0.0611

5                       1/16384(2002)       0.122188

6                        1/16384(3003)      0.1833

7                         1/16384(3432)      0.2095

8                        1/16384(3003)       0.1833

9                        1/16384(2002)       0.122188

10                       1/16384(1001)        0.0611

11                       1/16384(364)        0.02222

12                      1/16384(91)            0.00555                             0.006461

13                     1/16384(14)              0.00085                           0.000911

14                       1/16384(1)            0.000061                            0.000061

We use the cumulative and decumulative column as the critical region is composed of two portions of area ( probability) one in each tail of the distribution. If  alpha = 0.05 then alpha by 2 - 0.025 ( area in each tail).

We observe that P (X≤2) =   0.006461 > 0.025

and

P ( X≥12 ) = 0.006461 > 0.025

Therefore true significance level is

∝=  P (X≤0)+P ( X≥14 ) = 0.000061+0.000061= 0.000122

Hence critical region is (X≤0) and ( X≥14)

Computation x= 12

Since x= 12 (0.006461) does not fall in the critical region so we accept our null hypothesis and conclude that the coin is fair.

3 0
3 years ago
Moesha has 196 pepper plants that she wants to plant in square formation. How many peppers plants should she plant in each row?
miss Akunina [59]

Hey there!!

In order to solve this question, we take the area as 196 as these are the total number of plants to cover a specific place.

The formation must be in a square formation

area of a square = ( s ) ²

s = side

or the number of plants in a row

s² = 196

s = √196

s = 14

There are 14 plants in each row

Hope my answer helps!

8 0
3 years ago
Read 2 more answers
Order the following values least to greatest .
fgiga [73]

Answer:

2 3/10, 2.59, 24

Step-by-step explanation:

4 0
3 years ago
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Lady bird [3.3K]
Tan(58)=10/x
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3 0
3 years ago
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