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Levart [38]
1 year ago
12

3. Given AB with coordinates A(-4,5) and B(12,13). Find the horizontal distance and the vertical

Mathematics
1 answer:
SCORPION-xisa [38]1 year ago
6 0

The required distance would be 17.88 units coordinates A(-4,5) and B(12,13) and the horizontal distance is 16 units and the vertical distance is 8 units from A to B which are determined by the graphing method.

<h3>What is the distance between two points?</h3>

The distance between two points is defined as the length of the line segment between two places representing their distance.

Given AB with coordinates A(-4,5) and B(12,13).

The formula of the distance between two points is A(x₁, y₁) and B(x₂, y₂) is given by: d (A, B) = √ (x₂ – x₁)² + (y₂ – y₁) ².

x₁ = -4, y₁ = 5

x₂ = 12, y₂ = 13

distance = √ (12 – (-4))² + (13 – 5)²

distance = √ (12 + 4)² + (8)²

distance = √ (16)² + (8)²

distance = √ (256 + 64)

distance = √320

distance = 17.88 units

The horizontal distance is 16 units and the vertical distance is 8 units from A to B which are determined by the graphing method.

Learn more about the distance between two points here:

brainly.com/question/15958176

#SPJ1

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Answer: 1) Both gave same number of candies to each child.

2) Christov gave candy to a greater number of children.

Step-by-step explanation:

Since, Christov initially had 300 pieces of candy, and after he was visited by 17 children, he had 249 pieces left.

Let he gave x candy to each student when he visited 17 children.

Then, 17 x + 249 = 300

⇒ 17 x = 51

⇒ x = 3

Since, he distributes candies in a constant speed.

Therefore, his speed of distribution = 3 candies per child

Now,The function that shows the remaining number of candies Mateus has after distributing candies to n children,

C(n)=270 - 3 n

Initially, n = 0

C(0) = 270

⇒ Mateus has initial number of candies = 270

When he gave candies to one child then remaining candies = 270 - 3 × 1 = 267

Thus, the candies, get by a child from Mateus = 270 - 267 = 3

Since, he distributes candies in a constant speed.

⇒ His speed of distribution = 3 candies per child

1) Therefore, Both Christov and Mateus have same speed of distribution.

2) Since, both have same seed.

⇒ The one who has greater number of candies will be distribute more.

⇒ Christov will give more candies.


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