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Andrej [43]
1 year ago
6

Not yet answered Points possible: 1.00 The equivalence point of any acid-base titration can be determined visually from a titrat

ion curve by finding the place where Select one: O the curve levels off. O the curve has the steepest slope. O pH=7.
Chemistry
1 answer:
pshichka [43]1 year ago
7 0

The volume of the base should be gradually increased, stopping once the equivalence point is achieved. At the volume halfway between the equivalence point and the acid, the acid's pKa is equal to the pH.

<h3>What is titration, for instance?</h3>

Titration, sometimes referred to as titrimetry, is a method for calculating the concentration of a specific analyte in a mixture that is used in chemical qualitative analysis. Titration, which is also sometimes referred to as volumetric analysis, is a crucial analytical chemistry method.

<h3>What governs titration in its basic form?</h3>

The following is the fundamental titration principle: The sample being studied is given a solution, referred to as a titrant or standard solution. A chemical is present in the titrant in a known concentration.

To know more about Titration visit:

brainly.com/question/29590776

#SPJ4

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A student is asked to determine the molarity of a strong base by titrating it with 0.250 M solution of H2SO4. The students is in
tamaranim1 [39]

Answer:

The molarity of the strong base is 0.625 M

Which procedural error will result in a strong base molarity that is too high?

⇒ Using a buret with a tip filled with air rather than the H2SO4 solution

Explanation:

<u>Step 1:</u> Data given

Molarity of H2SO4 = 0.250 M

The initial buret reading is 5.00 mL

The final reading is 30.00 mL

<u />

<u>Step 2:</u> Calculate volume of H2SO4 used

30.00 mL - 5.00 mL = 25.00 mL

<u>Step 3:</u> Calculate moles of H2SO4

0.250 M = 0.250 mol/L

Since there are 2 H+ ions per H2SO4

0.250 mol/L  * 2 = 0.500 mol/L

The number of moles H2SO4 = 0.500 mol/L * 0.025 L

Number of moles H2SO4 = 0.0125 mol

<u>Step 4</u>: Calculate moles of OH-

For 1 mol H2SO4, we need 1 mol of OH-

For 0.0125 mol of H2SO4, we have 0.0125 mol of OH-

<u>Step 5</u>: Calculate the molarity of the strong base

Molarity = moles / volume

Molarity OH- = 0.0125 mol / 0.02 L

Molarity OH - = 0.625 M

Which procedural error will result in a strong base molarity that is too high?

⇒ Using a buret with a tip filled with air rather than the H2SO4 solution

   

5 0
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