Answer:
there are no valence electrons left over, so the molecule has four bond pairs and no lone pairs.
Explanation:
Types of Bonds can be predicted by calculating the
difference in electronegativity.
If, Electronegativity difference is,
Less
than 0.4 then it is Non Polar Covalent
Between 0.4 and 1.7 then it is Polar Covalent
Greater than 1.7 then it is Ionic
For Be and F,
E.N of Fluorine = 3.98
E.N of Beryllium = 1.57
________
E.N Difference 2.41 (Ionic Bond)
For H and Cl,
E.N of Chorine = 3.16
E.N of Hydrogen = 2.20
________
E.N Difference 0.96 (Polar Covalent Bond)
For Na and O,
E.N of Oxygen = 3.44
E.N of Sodium = 0.93
________
E.N Difference 2.51 (Ionic Bond)
For F and F,
E.N of Fluorine = 3.98
E.N of Fluorine = 3.98
________
E.N Difference 0.00 (Non-Polar Covalent Bond)
Result:
A polar covalent bond is formed between Hydrogen and Chlorine atoms.
Answer: 19.71 feet
Explanation:
Given: Speed of Charlotte =58.6 mi/h
Since 1 hour = 3600 seconds
and 1 mile = 5280 feet
So, Speed of Charlotte =
mi/ sec
She looks down at her phone and takes her eyes off the road for 4.36 s.
Since , Distance = ![\dfrac{speed}{time}](https://tex.z-dn.net/?f=%5Cdfrac%7Bspeed%7D%7Btime%7D)
So, Distance = ![\dfrac{85.95}{4.36}=19.71\ feet](https://tex.z-dn.net/?f=%5Cdfrac%7B85.95%7D%7B4.36%7D%3D19.71%5C%20feet)
Hence, Charlotte traveled 19.71 feet during this time.