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2 years ago

PLEASE HELP!!!

Chemistry

1 answer:

Lesechka [4]2 years ago

6 0

Find pH of all

pH=-log[H+]

pH=-log[3.5×10^{-5}]
pH=-log3.5+5
pH=4.4

pH=-log3.5+4
pH=3.4

pOH=-log[OH]

pOH=-log[1.3×10^{-10}]
pOH=-log1.3+10
9.8

pH=

14-9.8
4.2

pOH=-log6.2+11
pOH=10.2

14-10.2
3.8

So our answers

solution A is least acidic
solution A has the highest pH
solution A is most basic
solution B is least basic

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$\frac{6.626\times 10^{-34}\times 3\times 10^8}{260\times 10^{-9}}=3.68506\times 10^{-19}+\frac{1}{2}\times 9.11\times 10^{-31}\times v^2$

$3.68506\times \:10^{-19}+\frac{1}{2}\times \:9.11\times \:10^{-31}v^2=\frac{6.626\times \:10^{-34}\times \:3\times \:10^8}{260\times \:10^{-9}}$

$\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=7.64538\times 10^{-19}-3.68506\times 10^{-19}$

$\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=3.96032462\times 10^{-19}$

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