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Aleksandr-060686 [28]
2 years ago
12

PLEASE HELP!!!

Chemistry
1 answer:
Lesechka [4]2 years ago
6 0

Find pH of all

#A

pH=-log[H+]

  • pH=-log[3.5×10^{-5}]
  • pH=-log3.5+5
  • pH=4.4

#B

  • pH=-log3.5+4
  • pH=3.4

#C

pOH=-log[OH]

  • pOH=-log[1.3×10^{-10}]
  • pOH=-log1.3+10
  • 9.8

pH=

  • 14-9.8
  • 4.2

#4

  • pOH=-log6.2+11
  • pOH=10.2

pH

  • 14-10.2
  • 3.8

So our answers

  1. solution A is least acidic
  2. solution A has the highest pH
  3. solution A is most basic
  4. solution B is least basic

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Thickness = 0.28 mm = 0.28 \times \frac{1}{10} cm = 0.028 cm

Area = 0.40 m^{2} = 0.40 \times 10^{4} cm^{2} = 4000 cm^{2}

As, it is known that volume = area × thickness

So,             Volume = 4000 cm^{2} \times 0.028 cm      

                                = 112 cm^{3}

As density is mass divided by volume. So, mass of chromium will be calculated as follows.

                   Density = \frac{mass}{volume}  

            7.20 g/cm^{3} = \frac{mass}{112 cm^{3}}      

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As, mass of 1 mole of chromium is 52 g. So, number of moles in 806.4 g of chromium will be as follows.

              No. of moles = \frac{mass}{molar mass}                            

                                     = \frac{806.4 g}{52 g}

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In chromate ion, (CrO^{2-}_{4}) charge on Cr is +6. It means that 6 electrons are needed to reduce Cr^{+6} into Cr.

As, 1 mole of Cr^{+6} ions require 6 moles of electrons. Therefore, moles of electrons for 15.50 mol will be calculated as follows.

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To calculate number of electrons we multiply number of moles by Avogadro's number as follows.

               93.04 mol \times 6.02 \times 10^{23}

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There is magnitude of 6.241 \times 10^{18} times the charge on an electron is equal to 1 coulomb.

Hence, number of coulombs will be as follows.

              No. of coulombs = \frac{5.6 \times 10^{25}}{6.241 \times 10^{18}}

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or,                                        = 8.97 \times 10^{6} C

Thus, we can conclude that 8.97 \times 10^{6} C are required to plate a layer of chromium metal with given data.

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