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wariber [46]
1 year ago
8

you manage a network that has multiple internal subnets. you connect a workstation to the 192.168.1.0 subnet using the default s

ubnet mask. this workstation can communicate with some hosts on the private network, but not with other hosts. you run ipconfig /all and see the following:
Computers and Technology
1 answer:
NeX [460]1 year ago
6 0

The cause of the problem will be Incorrect default gateway.

A TCP/IP computer cannot communicate with external networks, but it can communicate with the systems on the LAN (as no router is required) if its configuration does not include a default gateway address.

Click the Start button, then choose Command Prompt from the context menu. Step 2: Type "ipconfig" into the Command Prompt window and hit [Enter]. The numbers listed in the Default Gateway section are the IP Address of your router.

30 seconds after unplugging the router, connect it back in. Reconnecting to the internet may take some time. Before continuing, get in touch with your Internet Service Provider if you're still having trouble connecting to the internet. Transfer the Ethernet connection from the Internet Gateway to another router port.

Learn more about default gateway:

brainly.com/question/2692918

#SPJ4

The complete question is ''You manage a network that has multiple internal subnets. You connect a workstation to the 192.168.1.0/24 subnet.

This workstation can communicate with some hosts on the private network, but not with other hosts. you run ifconfig /all and see the following.

Ethernet adapter Local Area Connection : Connection- specific DNS Suffix . : mydomain . local Description . .Broadcom network adapter

Physical Address . : 00 - AA-BB-CC-74-EF

DHCP Enabled . . . . . . . No

Autoconfiguration Enabled . Yes

IPv4 Address 192 . 168 . 1 . 102(Preferred)

Subnet Mask . 255 . 255 . 255 . 0

Default Gateway : 192 . 168 .2.1

DNS Servers . . 192 . 168 . 2 . 20

What is the most likely cause of the problem?

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4 years ago
Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server
sattari [20]

Answer:

The smallest number of servers required is 3 servers

<em />

Explanation:

Given

Reliability = 99.98\%

Individual Servers = 95\%

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

p = 95\%\\

It should be noted that probabilities always add up to 1;

So,

p + q = 1'

Subtract p from both sides

p - p + q = 1 - p

q = 1 - p

Substitute p = 95\%\\

q = 1 - 95\%

Convert % to fraction

q = 1 - \frac{95}{100}

Convert fraction to decimal

q = 1 - 0.95

q = 0.05

------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

p = 99.98\%

Recall that probabilities always add up to 1;

So,

p + q = 1

Subtract q from both sides

p + q - q = 1 - q

p = 1 - q

So,

p = 1 - q = 99.98\%

1 - q = 99.98\%

Let the number of servers be represented with n

The above expression becomes

1 - q^n = 99.98\%

Convert percent to fraction

1 - q^n = \frac{9998}{10000}

Convert fraction to decimal

1 - q^n = 0.9998

Add q^n to both sides

1 - q^n + q^n= 0.9998 + q^n

1 = 0.9998 + q^n

Subtract 0.9998 from both sides

1 - 0.9998 = 0.9998 - 0.9998 + q^n

1 - 0.9998 = q^n

0.0002 = q^n

Recall that q = 0.05

So, the expression becomes

0.0002 = 0.05^n

Take Log of both sides

Log(0.0002) = Log(0.05^n)

From laws of logarithm Loga^b = bLoga

So,

Log(0.0002) = Log(0.05^n) becomes

Log(0.0002) = nLog(0.05)

Divide both sides by Log0.05

\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}

\frac{Log(0.0002)}{Log(0.05)} = n

n = \frac{Log(0.0002)}{Log(0.05)}

n = \frac{-3.69897000434}{-1.30102999566}

n = 2.84310893421

n = 3 (Approximated)

<em>Hence, the smallest number of servers required is 3 servers</em>

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