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statuscvo [17]
3 years ago
8

Which is NOT a type of SD card?

Computers and Technology
2 answers:
andre [41]3 years ago
6 0
I'm pretty sure the answer is B.

SD SC can held up to 2GB capacity

SDHC can held up to 32 GB

SDXC (eXtended) can held up to 2TB

SDIO is an interface for I/O devices, there are cameras with this standard.
Vesnalui [34]3 years ago
3 0

Answer:

Your correct answer is B SD medium capacity

Explanation:

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What is the use of consonant in QBASIC ? Answer me in short and easy answer.​
Digiron [165]

Answer:

See Explanation

Explanation:

I'll assume the question is about the use of constants in QBasic because consonants do not have any special function or usage in QBasic.

In simple terms: In QBasic, constants are used to represent elements that do not change in value during program execution.

Take for instance, you intend to use \pi in your program.

Its value is \pi = 3.142

So, 3.142 will always be a constant in your program. One of the ways it can be used in a program is:

10 LET PI = 3.142

<em>The above represents a numeric constant. QBasic also have string constants.</em>

3 0
3 years ago
How can you get in touch with someone when they ain't answering you ☹
mixer [17]
You can go to their house and talk to them
3 0
3 years ago
Hãy mô tả mô hình xử lý của hệ thống thông <br> tin kế toán tài chính trong một doanh nghiệp
GrogVix [38]
Yes because it’s the square size of life
6 0
3 years ago
Which decimal number is equivalent to the hexadecimal number F1?
Papessa [141]

Answer:

C

Explanation:

8 0
3 years ago
Consider the following Stack operations:
maxonik [38]

Answer:

Sequence of popped values: h,s,f.

State of stack (from top to bottom): m, d

Explanation:

Assuming that stack is  initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:

push(d) -> enters d to the Stack

Stack:  

d ->top

push(h) -> enters h to the Stack

Stack:

h ->top

d ->bottom

pop() -> removes h from the Stack:

Stack:

d ->top

p: Suppose p contains popped values so first popped value entered to p is h

p = h

push(f) -> enters f to the Stack

Stack:

f ->top

d ->bottom

push(s) -> enters s to the Stack

Stack:

s ->top

f

d ->bottom

pop() -> removes s from the Stack:

Stack:

f ->top

d -> bottom

p = h, s

pop() -> removes f from the Stack:

Stack:

d ->top

p = h, s, f

push(m) -> enters m to the Stack:

Stack:

m ->top

d ->bottom

So looking at p the sequence of popped values is:

h, s, f

the final state of the stack:

m, d

end that is the top of the stack:

m

6 0
3 years ago
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