MCV = Hct × 10/RBC (84-96 fL) •Mean corpuscular Hb (MCH) = Hb × 10/RBC (26-36 pg) •Mean corpuscular Hb concentration (MCHC) = Hb × 10/Hct (32-36%) A rapid method of determining whether cellular indices are normocytic and normochromic is to multiply the RBC and Hb by 3.
Answer:
The answer to fill in the blank in this question: Some hormones act through cell membrane receptors that stimulate adenylate cyclase activity and production of:____, would be: cAMP.
Explanation:
In the process of hormonal regulation of cells there are two ways in which this can happen: direct activation of DNA inside a cell through steroid hormones, who do not need any kind of mediators to enter the cytoplasm of a cell and activate its genetic material, or indirect activation, which is the common way for non-steroidal hormones, such as epinephrine. In this second scenario a hormone will reach the cell and lock onto a receptor on the plasma membrane. The effect is that a G-protein, which is adjacent to the receptor, activates the second-messenger system, meaning that the activity the hormone came to initiate, will depend on these mediators. the G-protein will then activate adenylate cyclase, which in turn will activate ATP and transform it into cAMP. It is cyclic AMP (cAMP) which will finally relay the original message sent through the hormone, to the genetic material of the cell.
Answer:
The answer Icd 10 code J96
Explanation:
Because J96 is used to code Hypoxia. It is a condition in which the body or some area is deprived from oxygen supply. It can be general or partial, and it is a pahtological condition.
Hypercapnia is a condition in which there is an elevate amount of carbon dioxide in the blood. It usually happens as a result of hypoventilation, which is a consequence of the Hypoxia.
Answer:
clharithromycine
because it has toxic chemicAls fo use as well as killing