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MakcuM [25]
1 year ago
11

A rectangle has vertices at (0, 0), (3, 0), and (0,6). What is the area of the rectangle?

Mathematics
1 answer:
Alexxandr [17]1 year ago
7 0

First, set the coordinate points on a graph, and joint them to form a graph

By looking at the graph we can see that:

width : 3

length: 6

Area of a rectangle : Length x width : 6 x 3 = 18

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Max and Emma are discussing their math homework and disagree on the answer for one question. Max says that integers are closed u
hram777 [196]

A set has closure under an operation if performance of that operation on members of the set always produces a member of the same set; in this case we also say that the set is closed under the operation.

A closure property is a certain rule that holds <u>if it is true for all elements of a set under the given operation</u> and a closure property does not hold <u>if there is at least one pair of elements that do not follow the closure property under the given operation.</u>

Therefore, Emma is correct, because you can find a counterexample (7:2=3.5) that gives you a non-integer answer.

Answer: correct option is B

4 0
3 years ago
HELP ME PLEASE IM DUMB
m_a_m_a [10]

Answer:

-17/12

Step-by-step explanation:

-(2/3)-(3/4)

-(8/12)-(9/12)

-17/12

6 0
3 years ago
Out of 83 children, 39 are boys and 55 have been
Crank
Sounds like an id 10 t problem
5 0
3 years ago
Write the equation of this line in Point-Slope Form.​
Leona [35]

Answer:

y -3 = (-1/2)(x - 5)

Step-by-step explanation:

Slope of line:  Notice that if we go from 7 to 5, the 'run' is -2 and the corresponding 'rise' from 2 to 3 is 1.  Thus, the slope is m = -1/2.

Using m = -1/2 and the point (5, 3), we write the equation of this line in point-slope form as:

y -3 = (-1/2)(x - 5)

5 0
3 years ago
LAST ATTEMPT! MARKING AS BRAINLIEST!! ( simplifying radicals)
klasskru [66]

\huge \bf༆ Answer ༄

Let's solve ~

\qquad \looparrowright \sf - 2 \sqrt{192 {k}^{4} }

\qquad \looparrowright \sf - 2 \sqrt{2 {}^{6} \times   3{k}^{4} }

\qquad \looparrowright \sf - 2 \times 2 {}^{3}  \times  {k}^{2}   \times \sqrt{3}

\qquad \looparrowright \sf  - 16 {k}^{2}  \sqrt{3}

Hence, the correct choice is D

5 0
2 years ago
Read 2 more answers
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