All categories

2 years ago

John goes from a sauna at 115 Fahrenheit to an outside temperature of -30 Fahrenheit. What is the change in temperature?

Mathematics

1 answer:

IRINA_888 [86]2 years ago

7 0

Answer: 115 - (-30) = 115 + 30 = 145 degrees change

Step-by-step explanation:

You might be interested in

This lesson is almost ⅔ over. Express this number as a decimal.

MissTica

Answer:

0.66666667

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

HelP me plz i'll give brainliest or whatever

aivan3 [116]

The answer is d

explanation: its right in between 50 and 60 making it 55, and the picture is showing it as an angle.

3 0

3 years ago

Solve for p: a = 2πpw

MaRussiya [10]

Hello there.

<span>Solve for p: a = 2πpw

</span> $\frac{a}{6.283185w
}$

4 0

3 years ago

A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an

Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

$\tan\theta=\frac{perpendicular}{base}$

Here $\theta=45^{\circ}$ , perpendicular = 30 m and base we can find.

thus,

$\tan 45^{\circ}=\frac{30}{EA}$

We know $\tan 45^{\circ}=1$

thus, EA = 30 m

Consider the Δ AEB,

Using trigonometric ratio,

$\cos\theta=\frac{base}{hypotenuse}$

Here $\theta=60^{\circ}$ , hypotenuse = 80 m and base we can find.

thus, $\cos 60^{\circ}=\frac{base}{80}$

We know, $\cos 60^{\circ}=\frac{1}{2}$

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

4 0

3 years ago

The age of the Hawaiian islands gets older as you move from east to west. If the half-life of K-40 is 1.3 billion years, approxi

Mumz [18]

Answer:

$t \approx 750550.12\,yr$

Step-by-step explanation:

The time constant of the isotope is:

$\tau = \frac{1.3\times 10^{9}\,yr}{\ln 2}$

$\tau \approx 1.876 \times 10^{9}\,yr$

The decay of the isotope is described by the following model:

$\frac{m}{m_{o}} = e^{-\frac{t}{\tau} }$

Now, the time is cleared in the equation:

$t = -\tau \cdot \ln \frac{m}{m_{o}}$

$t = - (1.876\times 10^{9}\,yr)\cdot \ln 0.9996$

$t \approx 750550.12\,yr$

5 0

3 years ago