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7 months ago

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How do electromagnetic waves transfer energy without a medium?.

1 answer:

user100 [1]7 months ago

6 0

Since em waves are not conveyed by that of the vibration of electrons, they do not need a medium to travel. Electrical and magnetic fields, that could exist anywhere, oscillate, creating waves.

<h3>What do you mean by Electromagnetic waves?</h3>

The oscillations here between electrostatic potential and a magnetic field produce waves known as electromagnetic waves, or EM waves. In other words, magnetism fields oscillate to form electromagnetic (EM) waves.

<h3>Electromagnetic waves, where are they?</h3>

In contrast to wave propagation, electromagnetism waves can travel without a medium. This implies that microwaves can pass not only through stationary surfaces like air and rock but also through empty space.

To know more about Electromagnetic waves visit:

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An aqueous solution containing 10 g of an optically pure compound was diluted to 500 mL with water and was found to have a speci

lapo4ka [179]

Answer:

<u>Optical purity = 76.9231 %</u>

<u>Specific rotation of mixture = - 97.6923 °</u>

Explanation:

The mass of the racemic mixture = 3 g

It means it contains R enantiomer = 1.5 g

S enantiomer = 1.5 g

Amount of Pure R = 10 g

Total R = 11.5 g

Total volume = 500 mL + 500 mL = 1000 mL = 1 L

[R] = 11.5 g/L

[S] = 1.5 g/L

Enantiomeric excess = $\frac {Excess}{Total\ Concentration}\times 100$ = $\frac {11.5-1.5}{11.5+1.5}\times 100$ = 76.9231 %

<u>Optical purity = 76.9231 %</u>

Also,

Optical purity = $\frac {optical\ rotation\ of\ mixture}{optical\ rotation\ of\ pure\ enantiomer}\times 100$

Optical rotation of pure enantiomer = −127 °

$76.9231=\frac {optical\ rotation\ of\ mixture}{-127^0}\times 100$

<u>Specific rotation of mixture = - 97.6923 °</u>

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2 years ago

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Explanation:

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