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1 year ago

I don't understand would this be a linear function,quadratic function,or exponential function

Mathematics

1 answer:

Vaselesa [24]1 year ago

4 0

In the given figure there are 3 graphs

The line represents a linear function

$h(x)=x+2$

The parabola represents a quadratic function

$g(x)=2.5x^2+2x$

The third graph which approaches to the negative part o the x-xis is the exponential function

$f(x)=2^x$

The x-intercept of the line is (-2, 0)

x-intercept means intersect the x-axis at point (-2, 0)

There is only one graph that intersects the x-axis at (-2, 0)

It is the line, the linear function h(x)

The range is between 0 to infinity (0, ∞)

The range is the values of y

There is only one graph that has all values of y over the x-xis

it is f(x) the exponential function

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When a shape is rotated, it must be rotated around a point.

To determine the location of the new triangle, Sonja must subtract (5,-1) from the coordinates of the original triangle, before rotating by $90^o$ .

From the question, we have:

$C = (5,-1)$ --- the center of rotation

Let the vertices of the triangle be (x,y).

First, she must subtract the coordinates of the center of rotation from the vertices of the triangle.

This gives:

$(x,y) \to (x - 5, y + 1)$

Then the vertices are rotated by $90^o$

The rule of $90^o$ rotation is:

$(x,y) \to (-y,x)$

So, we have:

$(x - 5,y + 1) \to (-y - 1,x - 5)$

From the attachment, the coordinates of the triangle are: (0,2), (0,5) and (4,2)

After rotation, the coordinates are calculated as follows:

$(0,2) \to (-2-1,0-5) \to (-3,-5)$

$(0,5) \to (-5-1,0-5) \to (-6,-5)$

$(4,2) \to (-2-1,4-5) \to (-3,-1)$

Hence, the coordinates are: (-3,-5), (-6,-5) and (-3,-1)