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patriot [66]
3 years ago
15

Which statements are true about the trapezoid? not sure if i’m right

Mathematics
2 answers:
taurus [48]3 years ago
8 0
Yes you are absolutely right
Elena-2011 [213]3 years ago
6 0
From what I can see you are correct!
You might be interested in
Here is a rectangle ABCD.
lana66690 [7]

Answer:

32%

Step-by-step explanation:

Area of rectangle ABCD = 20 * 30 = 600 Sq cm

After increasing the length and width of the rectangle by 20% and 10% respectively.

New length = 30 + 20% of 30 = 30 + 6 = 36 cm

New width = 20 + 10% of 20 = 20 + 2 = 22 cm

Area of new rectangle = 36*22 = 792 Sq cm

Increase in area = 792 - 600 = 192 Sq cm

Percentage increase in area

= (192/600) *100

= 32%

5 0
3 years ago
Read 2 more answers
Need helpppp pleaseeeee
Temka [501]

Umm...

What is your question??? You have no question in the question box or attachments.

4 0
3 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. 2a2 − 30a + 108 = 0
Liono4ka [1.6K]
The quadratic formula is
- b +  -  \sqrt{ {b}^{2} - 4ac }  \div 2a
A = 2
B = -30
C = 108
plug in the values for the equation and you'll get what the factors are

-(-30)+√(-30)²-4(2)(108))/2(2)

and

-(-30)-√(-30)²-4(2)(108))/2(2)
This will give you your A values
and just round the answers from both of the above equations
8 0
4 years ago
Read 2 more answers
The unit price is $2.50
makkiz [27]

Answer:

The answer is 3.

Step-by-step explanation:

If you divide 7.50 by 2.50, you get 3. Hope this helps! And have an amazing day!

8 0
3 years ago
Read 2 more answers
Write the given expression in terms of x and y only. tan(sin^-1(x)+cos^-1(y))
Softa [21]

Answer:

[xy + √(1−x²) √(1−y²)] / [y √(1−x²) − x √(1−y²)]

Step-by-step explanation:

tan(sin⁻¹x + cos⁻¹y)

Use angle sum formula:

[tan(sin⁻¹x) + tan(cos⁻¹y)] / [1 − tan(sin⁻¹x) tan(cos⁻¹y)]

To evaluate these expressions, I suggest drawing right triangles.

For example, let's draw a triangle where x is the side opposite of angle θ, and the hypotenuse is 1.  Therefore:

sin θ = x/1

θ = sin⁻¹x

Using Pythagorean theorem, the adjacent side is √(1−x²).  Therefore:

tan θ = x / √(1−x²)

tan(sin⁻¹x) = x / √(1−x²)

Draw a new triangle.  This time we'll make y the adjacent side to angle θ.

cos θ = y/1

θ = cos⁻¹y

Using Pythagorean theorem, the opposite side is √(1−y²).  Therefore:

tan θ = √(1−y²) / y

tan(cos⁻¹y) = √(1−y²) / y

Substituting:

[x / √(1−x²) + √(1−y²) / y] / [1 − x / √(1−x²) × √(1−y²) / y]

Multiply top and bottom by √(1−x²).

[x + √(1−x²) √(1−y²) / y] / [√(1−x²) − x × √(1−y²) / y]

Multiply top and bottom by y.

[xy + √(1−x²) √(1−y²)] / [y √(1−x²) − x √(1−y²)]

3 0
3 years ago
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