<h3>
Answer: 21/10660</h3>
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Work Shown:
7 green + 12 blue + 19 yellow + 3 red = 41 total
A = probability of selecting red first (no replacement)
A = 3/41
B = probability of selecting green second (no replacement)
B = 7/40
C = probability of getting blue third (no replacement)
C = 12/39
D = probability of getting yellow fourth (no replacement)
D = 19/38 = 1/2
E = probability of getting red, green, blue, yellow in that order (no replacement)
E = A*B*C*D
E = (3/41)*(7/40)*(12/39)*(1/2)
E = (3*7*12)/(41*40*39*2)
E = 252/127920
E = 21/10660
When converting to decimal form, this is approximately 0.00196998
There's about a 0.196998% chance of getting this sequence of gumballs if they aren't replaced.
