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Sergeeva-Olga [200]

3 years ago

8

What is the approximate height of the silo? When measuring round to the nearest ¼ inch. Scale: ¼ inch = 5 feet

1 answer:

sesenic [268]3 years ago

3 0

Answer:

250 Po Sana makatutulong

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Solve for x and y:<br> x = 5 – 2y<br> 4y = 15 - 2x

Vika [28.1K]

Answer:

No solution.

Step-by-step explanation:

So we have the system of equations:

$x=5-2y\\4y=15-2x$

We can solve this by substitution. Substitute the first equation into the second. Thus:

$4y=15-2(5-2y)$

Distribute the right:

$4y=15-10+4y$

Subtract 4y from both sides:

$0=15-10$

Subtract the right:

$0=5$

As you can see, this statement is not true. In other words, the system of equations have no solution (likely because the lines are parallel).

And we're done!

7 0

3 years ago

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree)

Firdavs [7]

Is there a picture for this if so can you post it

8 0

3 years ago

A town has a population of 2000 and grows at 4% every year. What will be the population after 15 years, to the nearest whole num

sesenic [268]

Answer:

3602.

Step-by-step explanation:

The formula is:

Population after n years = 2000( 1.04)^n

After 15 years the population will be 2000(1.04)^15

= 3602.

5 0

3 years ago

( PLASE HELP ME) Solve the following equation.

vovikov84 [41]

Answer:

x = 2

Step-by-step explanation:

5(x-4) =-10

Distribute 5 by multiplying x and -4 by 5

5x - 20 = -10

Add 20 to both sides

5x - 20 + 20 = -10 + 20

5x = 10

Divide both sides by 5

5x ÷ 5 = 10 ÷ 5

x = 2

-Chetan K

7 0

3 years ago

Read 2 more answers

This is due like right now, please help me!!!!

Varvara68 [4.7K]

$\bold{\huge{\orange{\underline{ Solution }}}}$

$\bold{\underline{ Given \: Rules}}$

<u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
<u>The </u><u>sum </u><u>of </u><u>the </u><u>numbers </u><u>in </u><u>each </u><u>of </u><u>the </u><u>three </u><u>columns </u><u>is </u><u>the </u><u>same</u>
<u>The </u><u>sum </u><u>of </u><u>any </u><u>row </u><u>does </u><u>not </u><u>equal </u><u>the </u><u>sum </u><u>of </u><u>any </u><u>column </u>

$\bold{\underline{ Let's \: Begin}}$

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>

$\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }$

$\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}$

<u>According </u><u>to </u><u>the </u><u>first </u><u>rule </u><u>:</u><u>-</u><u> </u>

$\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}$

$\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}$

<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>

$\sf{ 158 + b = 166 + a, 156 + d = 166 + a }$

$\sf{ b = 166 - 158 + a, d = 166 - 156 + a }$

$\sf{ b = 8 + a, d = 10 + a ...(3)}$

<u>Subsitute </u><u>(</u><u>3</u><u>)</u><u> </u><u>in </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{229+a = 161+8+a+c = 168+10+a+e}$

$\sf{ 229+a = 169+a+c = 178+a+e}$

<u>We</u><u> </u><u>can </u><u>write </u><u>it </u><u>as </u><u>:</u><u>-</u>

$\sf{ 229+a = 169+a+c \:or\:229+a = 178+a+e}$

$\sf{ c = 299-169+a-a\:or\:e = 229-178+a-a}$

$\sf{ c = 60 \: and \: e = 51 }$

<u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>c </u><u>and </u><u>e </u><u>in </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

$\sf{ 158 + b = 156 + d = 166 + a = 78 + 60 + 51 }$

$\sf{ 158 + b = 156 + d = 166 + a = 189}$

<u>Now</u><u>, </u>

$\sf{ For \: b, 158 + b = 189 }$

$\sf{ b = 189 - 158 }$

$\sf{ b = 31}$

$\sf{ For \: d , 156 + b = 189 }$

$\sf{ d = 189 - 156 }$

$\sf{ d = 33}$

$\sf{ For \: a, 166 + a = 189 }$

$\sf{ a = 189 - 166 }$

$\sf{ a = 23 }$

Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .

8 0

3 years ago