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USPshnik [31]
1 year ago
11

Can someone help me with this please! I really need it done

Mathematics
1 answer:
natka813 [3]1 year ago
4 0

Using simple mathematical operations, the missing values are as follows:

(B) Dijon Mustard: 18g

  • Increased by 20 = 360g

(C) Barbeque sauce: 70g

  • Increased by 5 = 350g
  • Increased by 20 = 1,400g

(D) Worcestershire sauce: 10.35g

  • Increased by 5 = 51.75g
  • Increased by 20 = 207g

(E) Kosher salt: 1.5g

  • Increased by 5 = 7.5g
  • Increased by 20 = 30g

(F) Ground black pepper: 2.3g

  • Increased by 5 = 11.5g
  • Increased by 20 = 46g

(G) Crushed red pepper: 1.15g

  • Increased by 5 = 5.75g
  • Increased by 20 = 23g

<h3>What do we mean by mathematical operations?</h3>
  • A mathematical "operation" is the process of calculating a value utilizing operands and a math operator.
  • There are predefined rules associated with the math operator's symbol that must be applied to the supplied operands or numbers.
  • The order of operations is a rule that outlines the proper steps to take when analyzing a mathematical equation.
  • We can recall the PEMDAS steps in the following order: Parentheses, Exponents, Multiplication, Division (from Left to Right), Addition, and Subtraction (from left to right).

So, we can calculate missing values as follows:

(B) Dijon Mustard: 18g

  • Increased by 20 = 18×20 = 360g

(C) Barbeque sauce: 70g

  • Increased by 5 = 70×5 = 350g
  • Increased by 20 = 70×20 = 1,400g

(D) Worcestershire sauce: 10.35g

  • Increased by 5 = 10.35×5 = 51.75g
  • Increased by 20 = 10.35×20 = 207g

(E) Kosher salt: 1.5g

  • Increased by 5 = 1.5×5 = 7.5g
  • Increased by 20 = 1.5×20 = 30g

(F) Ground black pepper: 2.3g

  • Increased by 5 = 2.3×5 = 11.5g
  • Increased by 20 = 2.3×20 = 46g

(G) Crushed red pepper: 1.15g

  • Increased by 5 = 1.15×5 = 5.75g
  • Increased by 20 = 1.15×20 = 23g

Therefore, using simple mathematical operations, the missing values are as follows:

(B) Dijon Mustard: 18g

  • Increased by 20 = 360g

(C) Barbeque sauce: 70g

  • Increased by 5 = 350g
  • Increased by 20 = 1,400g

(D) Worcestershire sauce: 10.35g

  • Increased by 5 = 51.75g
  • Increased by 20 = 207g

(E) Kosher salt: 1.5g

  • Increased by 5 = 7.5g
  • Increased by 20 = 30g

(F) Ground black pepper: 2.3g

  • Increased by 5 = 11.5g
  • Increased by 20 = 46g

(G) Crushed red pepper: 1.15g

  • Increased by 5 = 5.75g
  • Increased by 20 = 23g

Know more about mathematical operations here:

brainly.com/question/28937023

#SPJ13

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Answer:

width of rectangle = 2R = (200/π) = 400/π meters

length of rectangle = 400 - π(200/π) = 400 - 200 = 200 meters

Step-by-step explanation:

The distance around the track (400 m) has two parts:  one is the circumference of the circle and the other is twice the length of the rectangle.

Let L represent the length of the rectangle, and R the radius of one of the circular ends.  Then the length of the track (the distance around it) is:

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This equation is a 'constraint.'  It simplifies to πR + L = 400.  This equation can be solved for R if we wish to find L first, or for L if we wish to find R first.  Solving for L, we get L = 400 - πR.

We wish to maximize the area of the rectangular region.  That area is represented by A = L·W, which is equivalent here to A = L·2R = 2RL.  We are to maximize this area by finding the correct R and L values.

We have already solved the constraint equation for L:  L = 400 - πR.  We can substitute this 400 - πR for L in

the area formula given above:    A = L·2R = 2RL = 2R)(400 - πR).  This product has the form of a quadratic:  A = 800R - 2πR².  Because the coefficient of R² is negative, the graph of this parabola opens down.  We need to find the vertex of this parabola to obtain the value of R that maximizes the area of the rectangle:        

                                                                   -b ± √(b² - 4ac)

Using the quadratic formula, we get R = ------------------------

                                                                            2a

                                                   -800 ± √(6400 - 4(0))           -1600

or, in this particular case, R = ------------------------------------- = ---------------

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            -800

or R = ----------- = 200/π

            -4π

and so L = 400 - πR (see work done above)

These are the dimensions that result in max area of the rectangle:

width of rectangle = 2R = (200/π) = 400/π meters

length of rectangle = 400 - π(200/π) = 400 - 200 = 200 meters

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