Question

There are three consecutive positive odd integers whose product of the first two is 44 less than the product of the second and third. Predict the sum of the three odd consecutive positive integers. A) 9 B) 27 C) 33 D) 39

Answer 1

The sum of three odd consecutive integers is 33.

Let the three consecutive odd integers be = (x-2),x,(x+2)

The product of first and second integers = (x-2)x

The product of second and third integers = x(x+2)

According to question, suitable equation is,

(x-2)x = x(x+2) - 44

$x^2-2x=x^2+2x-44\\4x=44\\x=11$

Hence the sum of the integers = (x-2)+x+(x+2) = 3x = 3*11 = 33.

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