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RUDIKE [14]
1 year ago
12

Please I need someone answer this page for me ?

Mathematics
1 answer:
larisa86 [58]1 year ago
3 0

\huge\mathcal {♨Answer♥}

(01)

  1. 0.9 , 323.5
  2. 2.156 , 4.777 , 87.669

(02)

  1. Tenths
  2. Tens
  3. Thousandths
  4. Hundredths
  5. Ones
  6. Ten Thousandths

(03) Yes, The xavier is correct.

8.953 > 8

8.953 < 9

8.953 is bigger than 8 and smaller than 9.

9.000 - 8.953 = 0.047

(04)

  1. 10
  2. 10
  3. 1000
  4. 1000
  5. 1000
  6. 100
  7. 1000
  8. 100
  9. 10

(05)

  1. 0.6
  2. 8.3
  3. 2.5
  4. 9.2
  5. 12.9
  6. 0.1

(06)

  1. 0.6
  2. 7
  3. 0.7
  4. 2
  5. 36.8
  6. 6.1 & 18.3

(07)

  1. 2.1
  2. 2.3
  3. 0.7
  4. 2.8
  5. 1.3

(08)

  1. 4.13
  2. 2.31
  3. 1.21
  4. 3.11
  5. 9.01

<u>☆</u><u>.</u><u>.</u><u>.</u><u>hope this helps</u><u>.</u><u>.</u><u>.</u><u>☆</u>

_♡_mashi_♡_

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(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

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With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

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