Answer:
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
Step-by-step explanation:
A 6000-seat theater has tickets for sale at $26 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of $185,400?
Let
x = number of tickets sold for $26
y = number of tickets sold for $40
x + y = 6000
x = 6000 - y
$26 × x + $40 × y= $185, 400
26x + 40y = 185400
Substitute
26(6000 - y) + 40y = 185400
156000 - 26y + 40y = 185400
Collect like terms
- 26y + 40y = 185400 - 156000
14y = 29400
y = 29400/14
y = 2100 tickets
x = 6000 - y
x = 6000 - 2100
x = 3900 tickets
Hence
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
Answer:
the answer is 3
Step-by-step explanation:
Answer:
1.6
Step-by-step explanation:
8/5=1.6
1.6 x 5 = 8
Answer:
Step-by-step explanation:
(9x-1)^-1/2 - (x+2)(9x-1)^-1/2
= (9x-1)^-1/2( 1 - (x + 2))
= (9x-1)^-1/2(-1 - x)
= -(x + 1)(9x-1)^-1/2
= -(x + 1) / (9x-1)^1/2
