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Shalnov [3]
1 year ago
14

3. A cell phone company offers two texting plans. People who use plan A pay10 cents for each text sent or received. People who u

se plan B pay 12 dollarsper month, and then pay an additional 2 cents for each text sent or received.3a. Write an inequality to represent the fact that it is cheaper for someoneto use plan A than plan B. Use x to represent the number of texts theysend.Your answer3b. Solve the inequality."O x> 150O x < 150O > 1.5O x< 1.5

Mathematics
1 answer:
dedylja [7]1 year ago
7 0

The Solution:

Given:

Plan A:

Each text sent or received cost $0.10.

If x=number of texts sent or received in a month, the total cost is:

0.1x

Plan B:

Users pay a fixed charge of $12 and an additional $0.02 for each text sent or received. So, we have the expression for the total charges as:

\begin{gathered} 12+0.02x \\ \text{ where x = number of texts sent or received.} \end{gathered}

Part (a)

Writing the inequality that shows that to use plan A is cheaper than using plan B, we have:

0.1x

Part (b)

Solving the inequality in part (a) above, we have:

\begin{gathered} 0.1x0.08x

Dividing both sides by 0.08, we have:

\begin{gathered} x

Therefore, the correct answer is [option 2]

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zysi [14]

Answer:

Therefore, we conclute that the map distance between A and C is 35 m.u..

Step-by-step explanation:

We know that the order of three loci is A B C, and the map distance between A and B is 15 m.u., and the map distance between B and C is 20 m.u. We calculate the map distance between A and C.

Therefore, we get

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What is equivalent to 7-2(x+2)&lt;-4-3(1-x)
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Step-by-step explanation:

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