Answer:
A
Step-by-step explanation:
Answer:
a c d b have fun but that is what I think I'm not sure
Answer:
![\log_{2} [\frac{x^{3}(x + 4)}{3}]](https://tex.z-dn.net/?f=%5Clog_%7B2%7D%20%5B%5Cfrac%7Bx%5E%7B3%7D%28x%20%2B%204%29%7D%7B3%7D%5D)
Step-by-step explanation:
We have to write the following logarithmic expression as a single logarithm.
The given expression is
![3\log_{2} x - [\log_{2} 3 - \log_{2}(x + 4)]](https://tex.z-dn.net/?f=3%5Clog_%7B2%7D%20x%20-%20%5B%5Clog_%7B2%7D%203%20-%20%5Clog_%7B2%7D%28x%20%2B%204%29%5D)
= 
{Since,
, from the properties of logarithmic function }
= 
{Since,
, which also a logarithmic property}
= ![\log_{2} [\frac{x^{3}}{\frac{3}{x + 4}}]](https://tex.z-dn.net/?f=%5Clog_%7B2%7D%20%5B%5Cfrac%7Bx%5E%7B3%7D%7D%7B%5Cfrac%7B3%7D%7Bx%20%2B%204%7D%7D%5D)
=
(Answer)
Answer:
<em>x = -3 and y = 0</em>
Step-by-step explanation:
<em>It would be more direct to apply elimination in this problem, rather than substitution:</em>
2x + 6y = -6 ⇒ 2x + 6y = -6 ⇒ 10x = - 30
+ 2(4x - 3y = -12) + 8x - 6y = -24
<em>Now let us solve for x through simply algebra:</em>
10x = -30,
<em>x = -3</em>
<em>Substitute this value of x into the first equation to get the value of y:</em>
2( -3 ) + 6y = -6,
-6 + 6y = -6,
6y = 0,
<em>y = 0</em>
Answer:
0.5
Step-by-step explanation: