B. 6(18c + 16r) = t
This shows her, in the parenthesis, exactly how many each shop should get.
C. 432 Carnations.
192 Roses
Simply multiply the bunches by the number in a bunch
D. Jake has 2.25 the number of carnations as roses. So he could use 9 carnations and 4 roses per grouping and that would give him an equal number with none left over.
4X + 7X = 33
11X = 33
X =3
So, 4*3 = 12, and 7*3= 21
9514 1404 393
Answer:
A, C, F, G, I
Step-by-step explanation:
A relation is "odd" if it is symmetrical about the <em>origin</em>. That is, f(-x) = -f(x). Here are the symmetries of the graphs shown:
A: origin
B: y-axis
C: origin, and x- and y-axes
D: x-axis
E: no symmetry
F: origin
G: origin, and x- and y-axes
H: x-axis
I: origin, and x- and y-axes
Well i do say that it has to be greater than 0
A= there are "4"one fourths in one hour and he hikes 2 miles every hour
B= 1, 1 1/2, 2, 4
C= it going to be 1/3 mile for every 1/6hour and she hikes 2 miles every hour.
D= 2/3, 1, 2, 4