Question

Three consecutive integers have a sum of 48 find the integers?

Answer 1

The sum of three consecutive integers is three times the middle one: if we call the middle one $x$, the three numbers are

$x-1,\ x,\ x+1$

So, their sum is $x-1+x+x+1 = 3x$

Which is three times the middle one.

So, if the sum of three consecutive intergers is 48, the middle one must be 48/3 = 16.

So, the three numbers are 15, 16 and 17