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3 years ago

Three consecutive integers have a sum of 48 find the integers?

1 answer:

6 0

The sum of three consecutive integers is three times the middle one: if we call the middle one $x$ , the three numbers are

$x-1,\ x,\ x+1$

So, their sum is $x-1+x+x+1 = 3x$

Which is three times the middle one.

So, if the sum of three consecutive intergers is 48, the middle one must be 48/3 = 16.

So, the three numbers are 15, 16 and 17

You might be interested in

In London today, four times the high temperature was more than twice the high temperature plus

4vir4ik [10]

Answer:

Let's define the high temperature as T.

We know that:

"four times T, was more than 2*T plus 66°C"

(i assume that the temperature is in °C)

We can write this inequality as:

4*T > 2*T + 66°C

Now we just need to solve this for T.

subtracting 2*T in both sides, we get:

4*T - 2*T > 2*T + 66°C - 2*T

2*T > 66°C

Now we can divide both sides by 2:

2*T/2 > 66°C/2

T > 33°C

So T was larger than 33°C

Notice that T = 33°C is not a solution of the inequality, then we should use the symbol ( for the set notation.

Then the range of possible temperatures is:

(33°C, ...)

Where we do not have an upper limit, so we could write this as:

(33°C, ∞°C)

(ignoring the fact that ∞°C is something impossible because it means infinite energy, but for the given problem it works)

4 0

3 years ago

Kevin entered a pie eating contest he ate 4 pies in 132 seconds what is Kevin going unit rate

8090 [49]

One pie every 33 seconds

6 0

3 years ago

What is the y-intercept of a line with the equation (y - 3) = 5(x + 2)?

Nookie1986 [14]

The y-intercept would be (0, 13)

7 0

2 years ago

Sin(3pi over 4) = _____

OlgaM077 [116]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2790456

______________

$\mathsf{sin\!\left(\dfrac{3\pi}{4}\right)}\\\\\\ =\mathsf{sin\!\left(\dfrac{3\cdot 180^\circ}{4}\right)}\\\\\\ =\mathsf{sin(135^\circ)}\\\\ =\mathsf{sin(180^\circ-135^\circ)}$

$=\mathsf{sin(45^\circ)}\\\\ =\mathsf{\dfrac{\sqrt{2}}{2}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps.=)

Tags: <em>sine sin common angles trig trigonometry </em>

8 0

3 years ago

Find a set of four integers such that their order and the order of their absolute values are the same.

Vinvika [58]

If you pick only positive numbers, the absolute value will have no effect, and the original set and the set of the absolute value will be exactly the same:

$A = \{1,2,3,4,5\}$

is still

$A = \{|1|,|2|,|3|,|4|,|5|\} = \{1,2,3,4,5\}$

8 0

3 years ago