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yanalaym [24]
3 years ago
8

Simplify: Negative four and one-fifth minus negative thirteen and one-tenth

Mathematics
1 answer:
olga_2 [115]3 years ago
3 0
-4 1÷5 - (- 13 1÷10)

first we should turn these into improper fractions by multiplying the whole number by the denominator then add the numerator.

4 × 5 = 20 + 1 = 21
13 × 10 = 130 + 1 = 131

(-21/5) - (-131/10)

To subtract fractions we want to find a common denominator so we can multiply the numerator and denominator of (-21/5) by 2 to get (-42/10)

(-42/10) - (-131/10)

Since we are subtracting a negative, that becomes a positive

(-42/10) + 131/10

131 - 42 = 89

89/10

Now we can change it back into a mixed fraction:

8 and nine-tenths or 8 9÷10
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See attachment for the graphs of: <em>y =x - 2, y = 0.4x - 2, y =-x - 2</em>

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We have:

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So, the equation is: \mathbf{y = 0.4x - 2} when k = 0.4

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See attachment for the graphs of: \mathbf{y = x - 2}, \mathbf{y = 0.4x - 2} and \mathbf{y = -x - 2}

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brainly.com/question/11804653

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3 years ago
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vlabodo [156]

Answer:

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Step-by-step explanation:

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this simplifies  divide the top and bottom by 5

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