Simplify: Negative four and one-fifth minus negative thirteen and one-tenth
1 answer:
-4 1÷5 - (- 13 1÷10)
first we should turn these into improper fractions by multiplying the whole number by the denominator then add the numerator.
4 × 5 = 20 + 1 = 21
13 × 10 = 130 + 1 = 131
(-21/5) - (-131/10)
To subtract fractions we want to find a common denominator so we can multiply the numerator and denominator of (-21/5) by 2 to get (-42/10)
(-42/10) - (-131/10)
Since we are subtracting a negative, that becomes a positive
(-42/10) + 131/10
131 - 42 = 89
89/10
Now we can change it back into a mixed fraction:
8 and nine-tenths or 8 9÷10
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i think you have to multiply the sides..
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I have a screenshot of the answer
First write it in vertex form :-
y= a(x - 2)^2 + 3 where a is some constant.
We can find the value of a by substituting the point (0.0) into the equation:-
0 = a((-2)^2 + 3
4a = -3
a = -3/4
so our equation becomes y = (-3/4)(x - 2)^2 + 3