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Nookie1986 [14]
1 year ago
12

Is (x-3) a factor of f(x) = x^2 - 32?

Mathematics
1 answer:
Leokris [45]1 year ago
3 0

Answer:

No

Explanation:

Here, we want to use the factor theorem to check if the given linear expression is a factor of the binomial

Now, according to the factor theorem, a factor of a polynomial would leave no remainder when divided by it

Mathematically, it means when we substitute the factor value into the polynomial, it is expected that the remainder is zero is the substituted is a factor of the polynomial

We set x-2 to zero:

\begin{gathered} \text{ x-2 = 0} \\ x\text{ = 2} \end{gathered}

Now, we substitute 2 into the polynomial as follows:

f(2)\text{ = }2^2-32\text{ = 4-32 = -28}

There is a remainder of -28 and thus, the linear factor is not a factor of the binomial

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I need the answer of this with steps and solutions fast plz​
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Step-by-step explanation:

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3 years ago
Can someone finish the whole thing ??
Romashka-Z-Leto [24]
<h3>Answer:    y = (3/2)x + 0</h3>

This is the same as  y = (3/2)x

=============================================================

Work Shown:

Find the slope of the line through (x1,y1) = (-2,-3) and (x2,y2) = (2,3)

m = (y2 - y1)/(x2 - x1)

m = (3 - (-3))/(2 - (-2))

m = (3 + 3)/(2 + 2)

m = 6/4

m = 3/2

The slope is the fraction 3/2. This is going to be in front of the x, or to the left of the x.

----------

Plug m = 3/2 and (x1,y1) = (-2,-3) into the point slope formula. Solve for y.

y - y1 = m(x - x1)

y - (-3) = (3/2)(x - (-2))

y + 3 = (3/2)(x + 2)

y + 3 = (3/2)x + (3/2)(2)

y + 3 = (3/2)*x + 3

y + 3 - 3 = (3/2)*x + 3 - 3

y = (3/2)x + 0

The y intercept is zero. This matches up with the fact the graph crosses the y axis at y = 0.

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3 years ago
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9 games multiply 0.6 to 15
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