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EleoNora [17]
3 years ago
6

Can someone finish the whole thing ??

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
3 0
<h3>Answer:    y = (3/2)x + 0</h3>

This is the same as  y = (3/2)x

=============================================================

Work Shown:

Find the slope of the line through (x1,y1) = (-2,-3) and (x2,y2) = (2,3)

m = (y2 - y1)/(x2 - x1)

m = (3 - (-3))/(2 - (-2))

m = (3 + 3)/(2 + 2)

m = 6/4

m = 3/2

The slope is the fraction 3/2. This is going to be in front of the x, or to the left of the x.

----------

Plug m = 3/2 and (x1,y1) = (-2,-3) into the point slope formula. Solve for y.

y - y1 = m(x - x1)

y - (-3) = (3/2)(x - (-2))

y + 3 = (3/2)(x + 2)

y + 3 = (3/2)x + (3/2)(2)

y + 3 = (3/2)*x + 3

y + 3 - 3 = (3/2)*x + 3 - 3

y = (3/2)x + 0

The y intercept is zero. This matches up with the fact the graph crosses the y axis at y = 0.

You might be interested in
How do you factorise x^2 - 9.
Zinaida [17]
X ^ 2 - 9

= x ^ 2 - 3 ^ 2

It turns into 3 ^ 2
Because 3 ^ 2 = 9

The final answer is
= ( x + 3 )( x - 3 )

remember the formula :

a^2 - b^2 =(a+b)(a-b)
4 0
3 years ago
The base pyramid below has a dimension of 16" x 16" a slant height of 17 inches in an altitude of 15 inches find the total surfa
pentagon [3]

Answer:

800 in²

Step-by-step explanation:

Applying,

TSA (A) = Area of the base+ Lateral area of the

A = lw+1/2ps................ Equation 1

Where l = lenght of the base, w = width of the base, p = perimeter of the base, s = slight height of the base.

But,

p = 2(l+w)............. Equation 2

Substitute equation 2 into equation 1

A = lw+1/2[2(l+w)s)

A = lw+s(l+w)............. Equation 3

From the question,

Given: l = 16 in, w = 16 in, s = 17 in

Substitute these values into equation 3

A = (16×16)+17(16+16)

A = 256+544

A = 800 in²

6 0
2 years ago
Two blocks are connected by a very light string passing over a massless and frictionless pulley. The 20.0 N block moves 75.0cm t
Angelina_Jolie [31]
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus, 
1.22 a = 12.0 - T  (eqn 1)
and for the 20.0 N block: 
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction) 
2.04 a = T - 6.5  (eqn 2) 

[eqn 1] + [eqn 2] → 3.26 a = 5.5 
a = 1.69 m/s² 


Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5 
T = 9.95 N 

Now want the resultant force acting on the 20.0 N block: 
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N 
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>

75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m 
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
3 0
2 years ago
The selling price of an item is $600. It is marked down by 30%, but this sale price is still marked up
Norma-Jean [14]

Answer:

7000

Step-by-step explanation:

divide 600 and 30 then multiply that answer by 350

7 0
3 years ago
Please help me!! I need help
Setler [38]

Answer:

c=l/--a^2+b^2=l/--45^2+20^2≈49.24429

Step-by-step explanation:

l/-- mean square root

^ means squared/ exponent

7 0
2 years ago
Read 2 more answers
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