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Montano1993 [528]
3 years ago
12

Can someone help me with this one I would appreciate it very much!!

Mathematics
1 answer:
jekas [21]3 years ago
6 0

Answer:

12.5 pounds

Step-by-step explanation:

16 ounces = 1 pound

200 ounces = 1 × 200/16 = 12.5 pounds

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A package states that there are 60 calories in 12 crackers and 75 calories in 15 crackers. Since the relationship is proportiona
Svetach [21]
There are 900 calories in 180 crackers. Write 60 calories for 12 crackers as 60/12. Then make x/180, showing that there are 180 crackers with an unknown amount of calories. Cross multiply 60 and 180, which is 10,800. Divide 10,800 by 12, and you get 900.
3 0
3 years ago
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Make an equation to represent the area of a square whose sides are given by the expression x + y
ki77a [65]

Answer:

x^2 + 2xy + y ^2

Step-by-step explanation:

A = a^2

a = x + y

(x + y) + (x + y)

x^2 + xy + xy + y^2

x^2 + 2xy + y ^2

4 0
3 years ago
Which graph represents the function f(x)=−3x−2?
LenaWriter [7]

Answer:

Top left

Step-by-step explanation:

We can plug in the y intercept to find which graph has the correct one.

x = 0 is y intercept

Thus

f(0) = -3^0-2 \\f(0) = -1-2\\f(0)=-3

At this point we known the y intercept is -3 so both graph in the left is considerable.

Notice that the base is the negative, thus the graph would goes down. Therefore the top left would be correct.

4 0
4 years ago
What is the following sum?<br>(please show how you worked it out)
AleksAgata [21]

Answer:

4\sqrt[3]{2}x(\sqrt[3]{y}+3xy\sqrt[3]{y} )

Step-by-step explanation:

Let's start by breaking down each of the radicals:

\sqrt[3]{16x^3y}

Since we're dealing with a cube root, we'd like to pull as many perfect cubes out of the terms inside the radical as we can. We already have one obvious cube in the form of x^3, and we can break 16 into the product 8 · 2. Since 8 is a cube root -- 2³, to be specific, we can reduce it down as we simplify the expression. Here our our steps then:

\sqrt[3]{16x^3y}\\=\sqrt[3]{2\cdot8\cdot x^3\cdot y}\\=\sqrt[3]{2} \sqrt[3]{8} \sqrt[3]{x^3} \sqrt[3]{y} \\=\sqrt[3]{2} \cdot2x\cdot \sqrt[3]{y} \\=2x\sqrt[3]{2}\sqrt[3]{y}

We can apply this same technique of "extracting cubes" to the second term:

\sqrt[3]{54x^6y^5} \\=\sqrt[3]{2\cdot27\cdot (x^2)^3\cdot y^3\cdot y^2} \\=\sqrt[3]{2}\sqrt[3]{27} \sqrt[3]{(x^2)^3} \sqrt[3]{y^3} \sqrt[3]{y^2}\\=\sqrt[3]{2}\cdot 3\cdot x^2\cdot y \cdot \sqrt[3]{y^2} \\=3x^2y\sqrt[3]{2} \sqrt[3]{y}

Replacing those two expressions in the parentheses leaves us with this monster:

2(2x\sqrt[3]{2}\sqrt[3]{y})+4(3x^2y\sqrt[3]{2} \sqrt[3]{y})

What can we do with this? It seems the only sensible thing is to look for terms to factor out, so let's do that. Both terms have the following factors in common:

4, \sqrt[3]{2} , x

We can factor those out to give us a final, simplified expression:

4\sqrt[3]{2}x(\sqrt[3]{y}+3xy\sqrt[3]{y} )

Not that this is the same sum as we had at the beginning; we've just extracted all of the cube roots that we could in order to rewrite it in a slightly cleaner form.

6 0
3 years ago
Holli's house is located at (−1, 4). She can walk in a straight line to get to Jedd's house. A fast food restaurant is located a
GrogVix [38]

Answer:

The coordinates of Jedd's house is   (-5, 0)

Step-by-step explanation:

Given;

Location of Holli's House =  (−1, 4)

Location of  fast food restaurant = (−3, 2)

To Find:

The coordinate of Jedd's house.

Solution:

If  the distance between the two points   (x_{1},y_{1}) and (x_{2},y_{2}) is divided by the point (x,y) in the ratio of m : n then

x=\frac{x_{1}n+x_{2}m}{m + n}

y=\frac{y_{1}n+y_{2}m}{m + n}

Hollis house is located at (-1 , 4)

So, (x_{1},y_{1}) = (-1 , 4)

She  walks in a straight line to get to Jedds house

The restaurant is located at (-3 , 2) and partitions the way from

(x , y) = (-3 , 2)

The ratio of  Hollis house to Jedds house  is 1 : 1

 (m : n) = 1 : 2

Lets consider that Jedds house is located at (x_{2},y_{2})

Then x_2 will be

-3=\frac{-1(1)+x_{2}(1)}{1+1}

-3=\frac{-1 +x_{2}}{2}

-3 \times 2=-1 +x_{2}

-6 = -1 +x_{2}

-6 = -1 +x_{2}

-5 =  x_{2}

Now y_{2} will be

2=\frac{4(1)+y_{2}(1)}{1+1}

2=\frac{4+y_{2}}{2}

2 \times 2=4+y_{2}

4 = 4+y_{2}

4  - 4 = y_{2}

y_{2} = 0

∴ The coordinates of Jedd's house is (-5, 0)

5 0
3 years ago
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