PLEASE HELP, 10TH GRADE GEOMETRY (REAL ANSWERS PLSSSS)
2 answers:
Answer:
The correct option is 4.
Step-by-step explanation:
Let the line AB divided into 7 equal parts.
It is given that point P partitions the directed line segment from A to B in 3:4. It means 3 parts are before P and 4 partes are after P.
It is given that point Q partitions the directed line segment from A to B in 4:3. It means 4 parts are before Q and 3 partes are after Q.
It is given that point R partitions the directed line segment from A to B in2:5. It means 2 parts are before R and 5 partes are after R.
It is given that point S partitions the directed line segment from A to B in 5:2. It means 5 parts are before S and 2 partes are after S.
From the below figure we can say that point S is closest to point B.
It is also written as
Therefore option 4 is correct.
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We can figure this out using the explicit formula.
n represents the term we are looking for.
f(1) represents the first term in the sequence, which in this case, is 7.
d represents the common difference, which in this case, is +3.
f(n) = 7 + 3(n - 1)
f(n) = 7 + 3n - 3
f(n) = 4 + 3n
Now, we can input 214 for n and solve.
f(214) = 4 + 3(214)
f(214) = 4 + 642
f(214) = 646
The 214th term in this sequence is 646.
n represents the term we are looking for.
f(1) represents the first term in the sequence, which in this case, is 7.
d represents the common difference, which in this case, is +3.
f(n) = 7 + 3(n - 1)
f(n) = 7 + 3n - 3
f(n) = 4 + 3n
Now, we can input 214 for n and solve.
f(214) = 4 + 3(214)
f(214) = 4 + 642
f(214) = 646
The 214th term in this sequence is 646.
Answer:
sorry..if mine became wrong
