Ask question

Ask question

All categories

1 year ago

10

What is 6.849 times ten to the fourth power minus 2.329 times ten to the negative second power express the answer in scientific

notation rounding to 2 decimal places.

1 answer:

maxonik [38]1 year ago

3 0

the answer in scientific notation rounding to 2 decimal places is given by 68490.98

What is 6.849 times ten to the fourth power minus 2.329 times ten to the negative second power express the answer in scientific notation rounding to 2 decimal places.

6.849 *(10)^4=6.849* 10000=68490

2.329*(10)^-2= 0.02329

according to the question

6.849 times ten to the fourth power minus 2.329 times ten to the negative second power

therefore 68490-0.02329

=68489.9767

round to 2 decimal

the answer in scientific notation rounding to 2 decimal places is given by 68490.98

learn more about of power here

brainly.com/question/14689105

#SPJ4

You might be interested in

Relay races called for 8 people on a team. There were 43 men and 34 women who wanted to race. How many teams could be formed ?ho

ELEN [110]

It would be an odd number of teams. What I did was add 43 and 34 together. Which gave me 77. So 77 people total wanted to race. There can only be 8 racers on each team. Each means to divide. So I divided 8 and 77. It gave me 9 with a remainder of 5. So there will e 9 teams and 5 racers left out. (:

4 0

2 years ago

Solve the problem.

julsineya [31]

Answer:

2 dogs

Step-by-step explanation:

2 dogs at 1st plus 7 dogs added equals 9

3 0

2 years ago

2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

2 years ago

i'm supposed to find the distance around this shape and i got it marked wrong on a test but i'm not sure why!

frutty [35]

The top is round so its 0

8 0

3 years ago

Read 2 more answers

Find the measure of VYX.

loris [4]

Step-by-step explanation:

follow the above attachment, hope this helps you.

4 0

2 years ago