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snow_tiger [21]

3 years ago

5

Mrs. habib has 46.25 feet of ribbon for a border around a bulletin board for her classroom.The board is 3.75 feet tall and 8.3 f

eet wide . how many feet
of ribbon will mrs habib have left after she puts border around the board.

1 answer:

Kisachek [45]3 years ago

4 0

46.25 - (2(3.75) + 2(8.3)) = 22.15 feet leftover.

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A rectangular building with a square base is being designed to minimize heat loss. The building designers state that the volume

Arturiano [62]

Answer:

y = 4000/x²

Step-by-step explanation:

The volume of the building is expressed as;

V = x²y where;

x is the length and width of the base.

y is the height of the building

Given

Volume V = 4000m³

Substitute the given volume into the equation as shown;

4000 = x²y

Make y the subject of the formula by dividing both sides by x²

4000/x² = x²y/x²

4000/x² = y

Rearrange

y = 4000/x²

Hence equation for y, the height of the building, in terms of x, the length and width of the base is expressed as y = 4000/x²

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2 years ago

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julia-pushkina [17]

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8 0

3 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

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If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

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OverLord2011 [107]

Answer:

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Step-by-step explanation:

41 = 12d - 7

48 = 12d

d = 4

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4 years ago

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Drupady [299]

Answer:

Hello its ok Love!

I believe x = 2 hope this helps good luck!

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3 years ago

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