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1 year ago

Laurie has a signed contract with I- Mobile where she will pay a $25 fee each month plus $2 per phone call.

Mathematics

1 answer:

nikitadnepr [17]1 year ago

8 0

Answer:

i dont know how your teacher teaches it but in the first question take away the y after the 25. number 2 the start equation would be 55=2x+25 then you would subtract 25 from each side to get 30=2x, the divide by to to get x=15 or she made 15 calls. number 3 is correct.

i hope this helps

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Carl. put $1.10 in his piggy bank every day in the month of July. His total savings was $55 at the end of June. hat is the best

Crank

Carl would have around $90 at the end of July

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3 years ago

Read 2 more answers

Can anyone help me do the questions that are circled with red and you don't need to do the graphing calculator thing, please

creativ13 [48]

Answer:

There are six problems circled in red.

As requested, only the analytical solutions are shown.

Question 16. Factor the polynomial

$44+15h+h^2$

Answer: (h + 4) (h + 11)

Question 17. Factor the polynomial

$40-22x+x^2$

Answer: (x - 2) (x -20)

Question 18. Factor the polynomial

$-24-10x+x^2$

Answer: (x - 12) (x + 2)

Question 19. Factor the polynomial

$-42-m+m^2$

Answer: (m - 7) (m + 6)

Question 20. Solve the equation

$x^2-7x+12=0$

Answer: x = 4 and x = 3

Question 22. Solve the equation

$x^2-6x=27$

Answer: x = 9 and x = - 3.

Explanation:

Question 16. Factor the polynomial

$44+15h+h^2$

1. Rearrange the terms:

$h^2+15h+44$

2. Open two parenthesis and place the common variable, h, as the first term of each.

$(h+a)(h+b)$

You are going to determine the values of a and b.

3. The values of a and b must satisfy that their product is 44 and their sum is 15.

a + b = 15 and a × b = 44

11 and 4 meet those conditions: 11 + 4 = 15, and 11 × 4 = 44.

So, the factored polynomial is:

$(h+4)(h+11)$

Question 17. Factor the polynomial

$40-22x+x^2$

1. Rearrange the terms:

$x^2-22x+40$

2. Write two binomials; each with first term x

(x-a)(x-b)

The negative sign for a comes from the negative sign before 22x; the negative sign of b comes from the product of the signs of -22x and + 40.

3. Find a and b such that a + b = 22 and a × b = 40

20 + 2 = 22 and 20 × 2 = 40, so the binomials are (x - 2) and (x - 20)

And the factored polynomial is:

$(x-2)(x-20)$

Question 18. Factor the polynomial

$-24-10x+x^2$

1. Rearrange the terms

$x^2-10x-24$

2. Sketch two binomials

$(x-a)(x+b)$

The negative sign for a corresponds to the negative sign for -10x, and the positive sign for b corresponds to the multplication of the signs of -10x and -4.

3. Find a and b such that their product is -24 and their aum is - 10.

Those numbers are - 12 and + 2:

- 12 + 2 = - 10
- 12 × (2) = - 24

Thus, the two factors are (x - 12) and (x +2).

And the factored polynomial is:

$(x-12)(x+2)$

Question 19. Factor the polynomial

$-42-m+m^2$

1. Rearrange the terms

$m^2-m-42$

2. Sketch the factors:

$(m-a)(m+b)$

The negative sign for a corresponds to the negative sign in front of m, the positive sign for b corresponds to the product of the signs of -m and -42.

3. Find two numbers, a and b, such that - a + b = - 1, and a × b = - 42

Those numbers are 6 and 7:

- 7 + 6 = - 1
-7 × 6 = - 42

Then, the factors are m - 7 and m + 6.

The factored polynomial is:

$(m-7)(m+6)$

Question 20. Solve the equation

$x^2-7x+12=0$

1. Factor the left side:

Find two numbers that sum -7 and their product is + 12. Those two numbers are - 4 and - 3.

$(x-4)(x-3)=0$

2. Use the zero product rule

x - 4 = 0 or x - 3 = 0

x = 4 or x = 3

Both, x = 4 and x = 3 are solutions.

Hence, the solutions are x = 4 and x = 3.

Question 22. Solve the equation

$x^2-6x=27$

1. Move 27 to the left side (using subtraction property of equalities):

$x^2-6x-27=0$

2. Factor the polynomial.

Find two numbers whose sum is - 6 and their product is - 27.

Those numbers are - 9 and + 3:

- 9 + 3 = - 6
- 9 × 3 = 27

$(x-9)(x+3)=0$

3. Zero product rule

$x-9=0\\ \\ x=9\\ \\ x+3=0\\ \\ x=-3$

The two solutions are: x = 9 and x = -3

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4 years ago

Find the probability of picking 2 blue marbles when 2 marbles are picked (with replacement) from a bag containing three blue and

Katen [24]

Answer: 0.5

Step-by-step explanation:

Given

There are 3 blue and 1 yellow marble

The chance of picking two marble out of 3 is $^3C_2$

The total no of ways of picking 2 marbles out of 4 is $^4C_2$

Therefore, the probability of picking 2 blue marbles

$\Rightarrow P=\dfrac{^3C_2}{^4C_2}\\\\\Rightarrow P=\dfrac{3\times 2}{4\times 3}\\\\\Rightarrow P=\dfrac{1}{2}$

3 0

3 years ago

(8x+1)(2x-3) as a simplified polynomial

Ugo [173]

Answer:

(8x+1)(2x-3) as a simplified polynomial

Step-by-step explanation:

I think this is the answer not sure

5 0

3 years ago

A box measure 4 units by 2.5by 1.5 units what is the greatest number of cubes with a side length of 1/2 unit that can pack insid

marin [14]

Answer:120

Step-by-step explanation:

Volume of box=length x width x height

Volume of box=4x2.5x1.5

Volume of box=15

Cube length=1/2=0.5

Volume of cube=0.5x0.5x0.5

Volume of cube=0.125

Number of cube that can be packed inside the box=15 ➗ 0.125=120

7 0

3 years ago