1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pogonyaev
3 years ago
15

What is the equation of this line in slope-intercept form?

Mathematics
1 answer:
Rudik [331]3 years ago
4 0
The answer is (b) y = 3x + 1
You might be interested in
Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean number of gallons of gasoline sold to his custom
ira [324]

Answer:

a) The best estimator for the population mean is given by the sample mean \hat \mu = \bar X = 5.70

b) The 99% confidence interval would be given by (4.969;6.431)    

c) We are 99% confident that the true mean for th number of gallons of gasoline  sold to his customers is between 4.969 and 6.431.

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1.9 represent the population standard deviation

n=45 represent the sample size  

2) Part a

The best estimator for the population mean is given by the sample mean \hat \mu = \bar X = 5.70

3) Part b. Develop a 99 percent confidence interval for the population mean.

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

5.7-2.58\frac{1.9}{\sqrt{45}}=4.969    

5.7+2.58\frac{1.9}{\sqrt{45}}=6.431

So on this case the 99% confidence interval would be given by (4.969;6.431)    

4) Part c. Interpret the meaning of part (b).

On this case we can say this: We are 99% confident that the true mean for th number of gallons of gasoline  sold to his customers is between 4.969 and 6.431.

4 0
3 years ago
What is the value of x to the nearest tenth?
saveliy_v [14]
\tan(\Theta) = \dfrac{\text{opp}}{\text{adj}}

\tan(43) =  \dfrac{x}{12}

x = \tan(43) \times 12

x = 11.2
7 0
3 years ago
Read 2 more answers
The table below shows the data for a random sample of fish that were collected from and later released into a lake:
Olin [163]

Answer:

244

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please help. Attached as an image
Triss [41]

Distance formula ds = v(dx² + dy²) s = ? v(1 + (dy/dx)²) dx ......... s = the arc length y = 171 - x²/45

chegg

someone solved it on this

https://youtu.be/UGjXlMVdZvc

4 0
2 years ago
To help consumers assess the risks they are​ taking, the Food and Drug Administration​ (FDA) publishes the amount of nicotine fo
Anni [7]

Answer:

The 90​% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 9 - 1 = 8

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.8595

The margin of error is:

M = T*s = 1.8595*2.7 = 5

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 25.3 - 5 = 20.3 milligrams

The upper end of the interval is the sample mean added to M. So it is 25.3 + 5 = 30.3 milligrams.

The 90​% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.

7 0
3 years ago
Other questions:
  • Given the function f(x) = 5x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.
    11·1 answer
  • rhonda had a piece of ribbon that was 5 feet 3 inches long she removed a 5-inch piece to us in her art project what is the lengt
    12·2 answers
  • Can you help me with this question
    15·1 answer
  • Simlify 1/2+5/8 and 2/3+ 1/4
    7·1 answer
  • 1. Which of the following conversions is possible?
    6·2 answers
  • Can Someone help me As Soon As Possible Please ​
    8·1 answer
  • At store A, rulers are sold individually. The cost y of x rulers is represented by the equation y = 0.95x. The costs of rulers a
    14·1 answer
  • Work out the area of this circle. Give your answer in terms of pie and state it’s units.
    8·1 answer
  • Please help answer the first 3 boxes for brainslt <br><br> &gt; for brainslt
    9·2 answers
  • Ufncunniufncfcnnuunr please heLlLpPpPpPpPppOpPp
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!