The population of weights for men attending a local health club is normally distributed with a mean of 178-lbs and a standard de
1 answer:
Answer:
183.4286 lbs
Step-by-step explanation:
given that the population of weights for men attending a local health club is normally distributed with a mean of 178-lbs and a standard deviation of 25-lbs.
Total weight in the lift should not exceed 6420 lbs
No of persons limited = 35
Hence average weight of the person that should be below
If the average exceeds 183.4286 pounds then the elevator would be considered overloaded.
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Answer:
8
Step-by-step explanation:
f(x) = (x+2)(x-2)
Substituting x=1 into f(x):
f(1) = 3*-1
= -3
Since -2 & 2 touch the x-axis, 1 has a negative y value, 2 has a y value of 0, and all values from 2, are positive.
Hence,
3, 4, 5, 6, 7, 8, 9, 10 are all positive. Therefore, the answer is 8
This can be confirmed with a graph, as attached below.
<em>Feel free to mark this as brainliest! :D</em>
