Answer:
30 dollars
Step-by-step explanation:
120/20=6
6x5=30
Hope this helped.
1 x 4 = 4
4 x 5 = 20
20 x 6 = 120
120 x 7 = 840
So the answer is 840
[1] There are two main values to science. The first is that mathematics is where we study numbers... and they appear everywhere in the world around us! We see whole numbers when we count, negative numbers when we are in debt (just look at the national debt!), fractions when we share things between people (think pizza, or chocolate bars, yum!), and decimals when we measure distances, lengths, areas, and sizes. In fact, numbers can be used to describe almost anything. Even color can be described as the amount of red, green, and blue light (the RGB system which is how computer screens work).
The second value to science is the thinking and ideas of mathematics. Mathematics is where we learn the ideas of distance and sizes (such as area and volume). It teaches us to ask, "How far?" or "How big?" These ideas are applied to study geography, biology, astronomy and more. We also learn to look for patterns. In math, these patterns are usually number or geometric patterns, but science applies this idea to discover patterns in the weather, agriculture, oceans, and more.
(Because I remember this question from FLVS)
Part A: The value of pi for both circles is 3.14.
Part B: The value of pi for both circles is 3.14.
Part C: The value of pi for both A and B is 3.14.
Let P be Brandon's starting point and Q be the point directly across the river from P.
<span>Now let R be the point where Brandon swims to on the opposite shore, and let </span>
<span>QR = x. Then he will swim a distance of sqrt(50^2 + x^2) meters and then run </span>
<span>a distance of (300 - x) meters. Since time = distance/speed, the time of travel T is </span>
<span>T = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x). Now differentiate with respect to x: </span>
<span>dT/dx = (1/4)*(2500 + x^2)^(-1/2) *(2x) - (1/6). Now to find the critical points set </span>
<span>dT/dx = 0, which will be the case when </span>
<span>(x/2) / sqrt(2500 + x^2) = 1/6 ----> </span>
<span>3x = sqrt(2500 + x^2) ----> </span>
<span>9x^2 = 2500 + x^2 ----> 8x^2 = 2500 ---> x^2 = 625/2 ---> x = (25/2)*sqrt(2) m, </span>
<span>which is about 17.7 m downstream from Q. </span>
<span>Now d/dx(dT/dx) = 1250/(2500 + x^2) > 0 for x = 17.7, so by the second derivative </span>
<span>test the time of travel, T, is minimized at x = (25/2)*sqrt(2) m. So to find the </span>
<span>minimum travel time just plug this value of x into to equation for T: </span>
<span>T(x) = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x) ----> </span>
<span>T((25/2)*sqrt(2)) = (1/2)*(sqrt(2500 + (625/2)) + (1/6)*(300 - (25/2)*sqrt(2)) = 73.57 s.</span><span>
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</span><span>mind blown</span>
