The range of this data is 65 since the minimum is 20 and the maximum is 85(if its counting by 5s) then you just subtract and you have the range.
Answer:
10
Step-by-step explanation:
If the sides of the rectangle is 6cm and 8cm, then we mean that, the length and breadth are 6cm and 8cm
The diagonal which cross at AX will be the hypotenus of the triangle formed by drawing the diagonal.
Hence,
Hypotenus = sqrt (opposite² + adjacent²)
AX = sqrt[(8²) + (6²)]
AX = sqrt(64 + 36)
AX = sqrt(100)
AX = 10
5^3 Sartre 10 + 4^3 sqrt 10
Answer:
x=8/7
Step-by-step explanation:
2/3=x/4+x/3
3x/12+4x/12=8/12
7x/12=8/12
x=(8/12)/(7/12)
x=(8/12)(12/7)
x=8/7
I am assuming you mean 4/7 as the sine or cosine cannot be higher than 1.
Lets find <span>θ,
</span>
θ = [sin-1](4/7) = 34.85 °
But lets take into account that this value is the equivalent in Quadrant I.
If Θ lies in Quadrant II , then θ = 180 ° - 34.85 ° = 145.15 °
So cosθ = cos (145.15) = -0.821
